In a 200 amp service, each leg carries 100 amps. However, since the legs are 180 degrees out of phase, you can achieve 240 volts across both legs. So, a 200 amp service typically consists of two 120 volt legs, each providing up to 100 amps.
The formula you are looking for is W = E x I. Watts = Volts x Amps.
You need the volts times the amps to equal 100 Watts. On 12 v that is 8.33 amps, or on 200 v is it 0.5 amps.
To supply 100 amps from 1.5 volts, you would need to use a very low resistance load. Using Ohm's Law (V = I*R), you can calculate that in order to achieve 100 amps with 1.5 volts, the load resistance would need to be approximately 0.015 ohms. Such low resistance loads can be challenging to find and may not be practical for most applications.
100 amps
A three wire home distribution service rated at 100 amps has a wattage capacity of;From L1 to L2 at 240 volts x 100 amps = 24000 watts or 24 kilowatts. From L1 to neutral at 120 volts x 100 amps = 12000 watts or 12 kilowatts. From L2 to neutral at 120 volts x 100 amps = 12000 watts or 12 kilowatts.
No
You should not load a 125 amp panel any more than 100 amps.
A three wire home distribution service rated at 100 amps has a wattage capacity of;From L1 to L2 at 240 volts x 100 amps = 24000 watts or 24 kilowatts. From L1 to neutral at 120 volts x 100 amps = 12000 watts or 12 kilowatts. From L2 to neutral at 120 volts x 100 amps = 12000 watts or 12 kilowatts.
If a 9V supply is connected to a 100-ohm resistor, then the current is not 2 Amps,or even close to it.I = E/R = 9/100 = 0.09 amp.
In a 200 amp service, each leg carries 100 amps. However, since the legs are 180 degrees out of phase, you can achieve 240 volts across both legs. So, a 200 amp service typically consists of two 120 volt legs, each providing up to 100 amps.
a 1.5 kVa source of electrical power has the capacity to supply 100 volts at 15 amps, 300 volts at 5 amps, or 1000 volts at 1.5 amps.
max. 100 amps then fuse blows.
The formula you are looking for is W = E x I. Watts = Volts x Amps.
A 24 volt DC power supply provides DC amps, not AC amps. You cannot draw 1.8 amps AC from a DC power supply, without some kind of inverter stage.That is the answer to the specific wording of the question. Now the answer to the question I think was originally intended...If 1.8 amps AC is being supplied to a 24 volt DC power supply, what would the current supplied by the power supply be?Power is volts times amps, so power supplied to the power supply is 120 VAC (assumed) times 1.8 amps, or 216 watts. If the power supply is 100% efficient, then the power input equals the power output, so use the some equation to take 216 watts and divide by 24 volts, and you get 9 amps.Keep in mind, this is ideal state, assuming 100% efficiency, and no real power supply will be that.
You need the volts times the amps to equal 100 Watts. On 12 v that is 8.33 amps, or on 200 v is it 0.5 amps.
To supply 100 amps from 1.5 volts, you would need to use a very low resistance load. Using Ohm's Law (V = I*R), you can calculate that in order to achieve 100 amps with 1.5 volts, the load resistance would need to be approximately 0.015 ohms. Such low resistance loads can be challenging to find and may not be practical for most applications.