You failed to state the input voltage.
To calculate the amps, use the formula:
Amps * Volts = Watts
X * volts = 6000
(If we guess at 12 Volts)
X * 12 = 6000
X = 6000/12
X = 500
Which is a pretty big fuses, but to make matters worse, you would need to add about 10% or more for power lost to the inefficiency of the inverter.
A 600 Amp fuse is an industrial device; hope you're planning on expensive.
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The 6000 watt rating will be the output wattage usually at 120 volts. 6000/120 = 50 amps. If the output is a three wire output at 240 volts the amperage will be 25 amps. For a 50 amp circuit a #6 copper conductor will be needed from a 60 amp breaker. For a 25 amp circuit a #10 copper conductor will be needed 30 amp breaker.
To determine the fuse size needed for a 6000-watt inverter, you would need to divide the power (in watts) by the voltage of the system (e.g., 12V or 24V) to get the current (in amps) drawn by the inverter. For a 12V system, around 500 amps would be required, so you may need a fuse above this value for safety. It's best to consult the inverter's specifications and guidelines to select the appropriate fuse size to protect the system.
No, watts are a measure of power while fuses are rated in amperes (amps). To determine the fuse rating, you need to calculate the current in amps by dividing the power in watts by the voltage. Then, choose a fuse that is rated equal to or slightly higher than the calculated current in amps.
You need the formula: Amps * Volts = Watts But you get to do the math.
No, you should not use a 10 amp fuse for a 1000 watt instant heater. To determine the appropriate fuse amperage, you can use the formula Watts = Volts x Amps to calculate the required amperage. For a 1000 watt heater operating at 120 volts, you would need a 10 amp fuse (1000 watts / 120 volts = 8.33 amps), but it's generally recommended to use a fuse with slightly higher amperage for safety margins.
A 15 amp fuse can handle a maximum load of 1800 watts, as watts = amps x volts. This calculation is based on the standard voltage in most residential settings, which is 120 volts.
The conversion of watts to amps at a fixed voltage is governed by the equation Amps = Watts/Volts for example 12 watts/12 volts = 1 amp for a US example, a food mixer with a 400 watt motor on a 120 volt supply 400/120 = 3.33amps, fit a 5amp fuse
I'm assuming the electrical system is single phase, such as a home. If not, you need to hire someone to do the work for you. First, 6000 watts at 120v is 50 amps, so if your load is truly 6000 watts, 30 amps isn't enough. If your 6000 watts is 240v, which would draw 25 amps, then 30 amps is plenty. Ten gauge wire may not be placed an a breaker or fuse larger than 30 amps.
No, watts are a measure of power while fuses are rated in amperes (amps). To determine the fuse rating, you need to calculate the current in amps by dividing the power in watts by the voltage. Then, choose a fuse that is rated equal to or slightly higher than the calculated current in amps.
You need the formula: Amps * Volts = Watts But you get to do the math.
Watts divided by volts = amps
The formula you are looking for is Watts = Amps x Volts. Amps = Watts/Volts. This comes to 4 amps load. Minimum size fuse would be 5 amps.
watts Divided by Volts = amps
You put it togather. If the lighter outlet is rated at 120 watts [that's 10 amps at 12 volts] maximum, then that means that the receptacle, wiring to it, and the fuse cannot carry a 300 watt [25 amps at 12 volts] load, AND SIMPLY PLUGGING IT IN, as suggested in answer 1 should result in blowing the fuse for that circuit. Do NOT let anyone talk you into replacing the 10A fuse with a 25A fuse, as that is a guarantee for burning up your wiring, and possibly your car. However, you do not mention whether the 300 watt rating for the inverter is the OUTPUT or INPUT RATING. IF, and ONLY IF, when you check the INPUT wattage rating [should be on a label or stamped into the outer cover of the inverter], if it indicates an INPUT rating of 120 watts [10 amps at 12 volts] or less, then you can just "plug it in." If the inverter input current rating exceeds 10 amps at 12 volts, then it will not work. To provide adequate power for your inverter, it would be necessary to add-on a new circuit from the battery, or the main fuse panel, with properly sized wire[s] for the load, a proprly sized fuse to protect the wire[s], and a socket also properly rated for the electrical load.j3h.
No, you should not use a 10 amp fuse for a 1000 watt instant heater. To determine the appropriate fuse amperage, you can use the formula Watts = Volts x Amps to calculate the required amperage. For a 1000 watt heater operating at 120 volts, you would need a 10 amp fuse (1000 watts / 120 volts = 8.33 amps), but it's generally recommended to use a fuse with slightly higher amperage for safety margins.
A 15 amp fuse can handle a maximum load of 1800 watts, as watts = amps x volts. This calculation is based on the standard voltage in most residential settings, which is 120 volts.
The conversion of watts to amps at a fixed voltage is governed by the equation Amps = Watts/Volts for example 12 watts/12 volts = 1 amp for a US example, a food mixer with a 400 watt motor on a 120 volt supply 400/120 = 3.33amps, fit a 5amp fuse
The basic equation is Watts divided by Volts equals Amps W/V = A
The 5 amp fuse has many wattages that it can protect. It depends on the voltage of the circuit that the fuse is protecting. Use the following formula, Watts = Volts x Amps. For example 120 volts x 5 amps = 600 watts, 240 volts x 5 amps = 1200 watts, 480 volts x 5 amps = 2400 watts and 600 volts x 5 amps = 3000 watts.