To calculate the output amps of a 600kVA generator at 240V, you would use the formula Amps = kVA / Volts. In this case, it would be 600kVA / 240V = 2500 amps.
The formula to calculate the relationship between amps, volts and watts is Volts X Amps = Watts or Volts = Watts / Amps or Amps = Watts / Volts therefore; 200 Watts divided by 1.95 Amps is 102.5641 Volts.
A 2000 watt generator at 120 volts would output approximately 16.67 amps (2000 watts / 120 volts = 16.67 amps).
41.666 amps. Divide watts by volts.
watts = volts * amps--> Amps = watts/ volts therefore; 2000/220= 9.09 amps
To calculate the output amps of a 600kVA generator at 240V, you would use the formula Amps = kVA / Volts. In this case, it would be 600kVA / 240V = 2500 amps.
The formula is volts times amps equals watts, or watts divided by volts equals amps.
The formula you are looking for is , A = kva x 1000/Volts.
That alternator produces 136 amps.
160 amps at 12v.
160 amps at 12v.
Ohm's law: Volts = Amps * Ohms, or Amps = Volts / Ohms 12 volts / 0.5 ohms = 24 amps
4 volts and how many amps? Watts = amps x volts. It depends on the amount of current (in Amps) flowing at 4 Volts... See Ohms Law: Watts = Volts x Amps If you have 2 Amps flowing at 4 Volts you are dissipating/consuming 8 Watts. If you have 10 Amps flowing at 4 Volts you are dissipating/consuming 40 Watts.
The formula to calculate the relationship between amps, volts and watts is Volts X Amps = Watts or Volts = Watts / Amps or Amps = Watts / Volts therefore; 200 Watts divided by 1.95 Amps is 102.5641 Volts.
It depends on how many Amps (current) are applied to the voltage. Watt = Volts x Amps. e.g. 12 volts @ 5 amps = 60 watts
It's not that simple. The basic formula is Volts / Ohms = Amps. For 30 Volts you'd get 0.5 Amps, for 60 Volts you'd get 1 Amp, for 120 Volts you'd get 2 Amps.
It depends on what the output voltage is. You only specified the input voltage, not the output voltage. The equation is 75 Kva = {some} amps times {some} kilovolts. (Minus incidental losses, of course, but you still need to know output volts.)