Yes, in this experiment, the variable "alcohol" refers to the liquid being tested to see how many drops can fit on a penny. By changing the type of alcohol used, you can observe how it affects the number of drops that can fit on the penny due to variations in surface tension and viscosity.
On average, a person's mouth can hold about 1-1.5 teaspoons of water comfortably. This would equate to roughly 75-115 drops of water, depending on the size of the droplets.
There are approximately 20 drops per milliliter, and 29.6 milliliters per ounce.So, 8 ounces of water would contain approximately:8 ounces X 29.6 mL/oz X 20 drops/mL= 4736 drops.There is no "standard" drop volume, so this is an approximation.
Ideally, everyone performing the experiment would include the following: - distilled waterThere are a lot of factors involved. The cohesion and adhesion ('stickiness') of water molecules can be effected by things like oils (on surface pennies from peoples' skin) and other contaminates on the penny. The size of the dropper or pipette will determine the size of each water droplet - the larger the drop, the fewer number of drops will fit on the penny. The manner in which the water is added to the penny is also a factor. Water has a cohesive nature (the molecules are kind of like magnets and are attracted to one another). Therefore, if the drop from the pipette is allowed to touch the water already on the surface of the penny, the water can be 'pulled' out of the dropper. When this happens, the size (volume) of the drop is not always the same - it could be a very small amount (which will result in a very large number of drops), or a large amount. Soap causes the cohesiveness ('stickiness') of the water molecules to decrease so they are not as strongly attracted to each other. Because of this, when soap is added to the water the number of drops that can be placed on the penny will decrease. The water molecules can't 'stick' together as well, so the water on top of the penny spills off sooner than it would with non-soapy water. Ideally, everyone performing the experiment would include the following: - distilled water (to start with) - same type/size of calibrated dropper/pipette - same date of penny - penny cleaned as thoroughly as possible using same cleaning procedure - same 'dropping' procedure
The volume of a quarter coin is 808.53 mm cubed (assuming it's not worn thin). In theory you could fit 1000 000 /808.53 = 1236.81 quarters in a litre. However, that assumes you can fill all the space and you can't do that because of the fixed cylindrical shape of the quarters. You would have to look at how many coins would fit in your particular shape.
About 10
four
Approximately 30 to 35 drops of water can fit on a US penny before spilling over. The surface tension of the water allows it to form a dome-like shape on top of the penny, holding more drops than you might expect.
Yes, in this experiment, the variable "alcohol" refers to the liquid being tested to see how many drops can fit on a penny. By changing the type of alcohol used, you can observe how it affects the number of drops that can fit on the penny due to variations in surface tension and viscosity.
The controlled variable is the penny. The independent variable is the water. The dependent variable is the amount of water able to fit on the penny.
On average, a person's mouth can hold about 1-1.5 teaspoons of water comfortably. This would equate to roughly 75-115 drops of water, depending on the size of the droplets.
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Alot of drops fit because if you keep the surface tension from moving then you could put as much drops as you can.] ==If you put a penny on a flat surface and keep its tension and keep the penny from moving you can put as much drops as you can till it leaks off. You cant put as much as you want cause the penny will overflow. its not a big object?
10
The answer obviously depends on the size of the prism!
Fine the area of the jar then find the area of a quarter then divide the area of the jar by the area of the quarter and you get your answer.
There are approximately 20 drops per milliliter, and 29.6 milliliters per ounce.So, 8 ounces of water would contain approximately:8 ounces X 29.6 mL/oz X 20 drops/mL= 4736 drops.There is no "standard" drop volume, so this is an approximation.