One Cubic foot is 1' x 1' x 1'. So it depends on how deep you are going. If you have
1 cu ft. of sand it will cover 12 sq.ft. at 1" thick. 4 sq.ft coverage at 3" thick. So depending on details you can't really answer your question. Hope this helps.
To calculate the volume of stone needed, first convert the depth to feet (2 inches = 1/6 feet). Then multiply the area (21x10 = 210 square feet) by the depth (1/6 feet) to find the volume in cubic feet: 210 sq ft * 1/6 ft = 35 cubic feet of stone.
There are 27 cubic feet in a cubic yard.
There are 33.57 gallons in 4.5 cubic feet.
None. Cubic feet means a volume and square feet means an area. You need a third dimension for cubic feet.
27 cu feet = 1 cu yard 1260 cu ft = 1260/27 = 46.67 (462/3) cu yards
The cubic yards require that the width of the pile also be given. Assume the width of the pile of dirt, w , is 80 feet. V = ( L ) ( w ) ( h ) V = ( 300 ft ) ( 80 ft ) ( 10 ft ) = 240 x 10^3 cu ft V = ( 240 x 10^3 cu ft ) ( 1 cu yd / 27 cu ft ) V = 8889 cu yd <------------------
100 cu ft × 2 = 200 cu ft.
If the dimensions given are inches, there are 49.11 cu. ft. If they are in feet there are 84,864 cu. ft.
1 cu ft = 0.037037 cu yeard
sq feet to sq yards cu ft to cu yards you need depth added to your sq ft to get cu ft such as 70 sq ft x 4 in deep = 23.33 cu ft =.086 cu yd
27 cu. ft. = 1 cu. yd.
A little more than one cubic yard of crushed rock is needed. (10 ft x 6 ft x 1/6 ft = 10 cu ft = 1 cu yd + 1 cu ft)
5 cu/yrds x 27 cu/ft = 135 cu/ft
1 ft = 12 in → 1 in = 1/12 ft Volume required to cover is 90 sq ft × 1 in = 90 sq ft × 1/12 ft = 7.5 cu ft → number of bags = 7.5 cu ft ÷ 0.8 cu ft/bag = 9.375 bags → you need to buy 10 bags
51840 cu ft
797 cu yards = 797 * 33 cu feet = 21519 cu ft.
10 ft x 10 ft x 12"(1 ft) = 100 cubic feet or 4 cubic yards (3ft x 3ft x 3ft = 27 cu ft or 1 cu yd))