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10 gallons..

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14y ago
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1mo ago

Let x represent the amount of 12% solution and (10-x) represent the amount of 20% solution. The equation to solve is: 0.12x + 0.20(10-x) = 0.14(10). Solving for x gives x = 4, so you need 4 gallons of the 12% solution and 6 gallons of the 20% solution to make 10 gallons of the 14% solution.

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Q: How many gallons of a 12 percent indicator solution must be mixed with a 20 percent indicator solution to get 10 gallons of a 14 percent solution?
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How many gallons of a 80 percent acid solution must be mixed with 60 gallons of a 16 percent solution to obtain a solution that is 60 percent?

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