Wiki User
∙ 14y agoThe answer is zero. You have asked the question incorrectly.
Wiki User
∙ 14y agoTo find the grams of LiOH in the solution, we need to use the percentage concentration of NaOH to calculate the molarity of the solution first. Then, we can use stoichiometry to convert the moles of NaOH to LiOH since they are in a 1:1 ratio. Finally, we can convert the moles of LiOH to grams using its molar mass.
This solution contain 26,3 g NaOH.
To determine the grams of KHP required, you first need to calculate the number of moles of NaOH present in the 50 mL solution. Then, using the balanced chemical equation of the titration between NaOH and KHP, you can find the mole ratio. From the mole ratio and the moles of NaOH, you can calculate the moles of KHP needed and then convert that to grams of KHP.
To find the mass of NaOH, first calculate the number of moles in 290 mL of a 1.7 M solution using the formula: moles = concentration (M) x volume (L). Then, use the molar mass of NaOH (40 g/mol) to convert moles to grams: mass = moles x molar mass.
To calculate the grams of NaOH in the solution, first convert the volume from milliliters to liters by dividing by 1000. Then use the formula: moles = molarity x volume. Finally, multiply the moles of NaOH by its molar mass (40 g/mol) to find the grams. In this case, it would be: (5.7 mol/L) x (0.35 L) x (40 g/mol) = 79.8 grams of NaOH.
To prepare 200ml of 10% NaOH solution, you would need to mix 20ml of NaOH with 180ml of water. Start by measuring out 20ml of NaOH solution, then add it to a container with 180ml of water. Mix thoroughly to ensure the NaOH is fully dissolved in the water.
A 50% NaOH aqueous solution means that the solution contains 50% sodium hydroxide (NaOH) by weight and the rest is water. This concentration indicates that for every 100 grams of the solution, 50 grams is NaOH.
To calculate the grams of NaOH in the solution, you first need to find the moles of NaOH present in 400.0 ml of the solution. The moles of NaOH can be calculated using the formula: moles = molarity x volume (in liters). Once you have the moles of NaOH, you can then calculate the grams using the formula: grams = moles x molecular weight.
To make a 10% NaOH solution, you would need 100 grams of NaOH per liter of water. So to make 1 liter, you would need 100 grams of NaOH.
To prepare a 30% NaOH solution, you would mix 30 grams of NaOH with enough water to make 100 grams of final solution. Be sure to use caution when handling NaOH as it is a caustic substance and can cause skin and eye irritation.
This solution contain 26,3 g NaOH.
To prepare a 1N NaOH solution, you would need to dissolve 40 grams of NaOH in water to make 1 liter of solution. This amount is used because 1N solution means 1 mole of NaOH per liter of solution, and the molar mass of NaOH is 40 g/mol, so 40 grams of NaOH is needed to have 1 mole in 1 liter of solution.
To calculate the grams of NaOH in the solution, first convert the volume from milliliters to liters by dividing by 1000. Then use the formula: moles = molarity x volume. Finally, multiply the moles of NaOH by its molar mass (40 g/mol) to find the grams. In this case, it would be: (5.7 mol/L) x (0.35 L) x (40 g/mol) = 79.8 grams of NaOH.
To calculate the grams of NaOH in the solution, first determine the moles of NaOH using the molarity and volume. Then, convert moles to grams using the molar mass of NaOH. The molar mass of NaOH is 40 g/mol.
To calculate the grams of sodium hydroxide present in the solution, first calculate the number of moles using the formula: moles = Molarity (M) x Volume (L). Then, use the molar mass of sodium hydroxide (NaOH) to convert moles to grams. The molar mass of NaOH is 40 g/mol. Thus, in this case, you have 0.3375 moles of NaOH and if you convert this to grams, it would be 13.5 grams.
A 50% purity solution of NaOH would contain 500 grams of NaOH per liter of solution. Given that the density is 1.53 g/mL, there would be approximately 327.5 grams of NaOH in one liter of solution (1.53 g/mL * 1000 mL).
To calculate the grams of solute, you need to first find the molar mass of NaOH (40 g/mol). Then, use the formula grams = moles x molar mass. The moles of NaOH in 1.8 L of a 3.5 M solution is 6.3 moles. Therefore, the grams of NaOH in 1.8 L of a 3.5 M solution is 252 grams.
To calculate the grams of NaOH in 500mL of 0.5M NaOH, you first need to find the moles of NaOH present in 500mL, which is 0.25 moles. Then, use the molar mass of NaOH (40g/mol) to convert moles to grams. So, in 500mL of 0.5M NaOH, there are 10 grams of NaOH.