i think that you have to add 100 gramd to produce the amount of 900 grams
In chemistry, the outcome of a reaction must have the same mass as the initial state. This means that if you have 32g of oxygen and 4g of hydrogen, you just have to add the numbers to discover the original mass (in this case, 36g).
To determine the amount of oxygen that reacted when burning hydrogen, we can use the balanced chemical equation for the combustion of hydrogen: 2 H₂ + O₂ → 2 H₂O. From the equation, 2 moles of hydrogen produce 2 moles of water, meaning 1 mole of hydrogen produces 1 mole of water. Given that 24.2 grams of hydrogen (approximately 12.1 moles) produce 216 grams of water (approximately 12 moles), we can see that 12 moles of water would require 6 moles of oxygen, which corresponds to about 192 grams of oxygen. Thus, approximately 192 grams of oxygen reacted.
The percentage of oxygen is 54,84 %.
When hydrogen and oxygen chemically combine to form water (H₂O), the mass ratio of hydrogen to oxygen is approximately 1:8. This is based on the molar masses, where hydrogen has a molar mass of about 1 gram per mole and oxygen about 16 grams per mole. Therefore, for every 2 grams of hydrogen, there are about 16 grams of oxygen in water, maintaining that 1:8 ratio.
800 g oxygen are needed.
In chemistry, the outcome of a reaction must have the same mass as the initial state. This means that if you have 32g of oxygen and 4g of hydrogen, you just have to add the numbers to discover the original mass (in this case, 36g).
When 2.5 moles of oxygen react with hydrogen, they react in a 1:2 ratio to produce water. Therefore, 2.5 moles of oxygen will produce 5 moles of water. To convert moles to grams, you'll need to know the molar mass of water, which is approximately 18 grams/mol. So, 2.5 moles of oxygen will produce 90 grams (5 moles x 18 grams/mole) of water.
To determine the amount of oxygen that reacted when burning hydrogen, we can use the balanced chemical equation for the combustion of hydrogen: 2 H₂ + O₂ → 2 H₂O. From the equation, 2 moles of hydrogen produce 2 moles of water, meaning 1 mole of hydrogen produces 1 mole of water. Given that 24.2 grams of hydrogen (approximately 12.1 moles) produce 216 grams of water (approximately 12 moles), we can see that 12 moles of water would require 6 moles of oxygen, which corresponds to about 192 grams of oxygen. Thus, approximately 192 grams of oxygen reacted.
The percentage of oxygen is 54,84 %.
The proportion by mass of hydrogen to oxygen in hydrogen peroxide is 1:16. This means that for every 1 gram of hydrogen in hydrogen peroxide, there are 16 grams of oxygen.
Petrol contains about 84% carbon and 16% hydrogen by weight so a litre weighing 700 grams contains 588 grams of carbon and 112 grams of hydrogen. In the engine it would burn with 2464 grams of oxygen to produce 2156 grams of CO2 and 1008 grams of water (steam), which is normally invisible but can be seen in the exhaust gases from a cold engine.
When hydrogen and oxygen chemically combine to form water (H₂O), the mass ratio of hydrogen to oxygen is approximately 1:8. This is based on the molar masses, where hydrogen has a molar mass of about 1 gram per mole and oxygen about 16 grams per mole. Therefore, for every 2 grams of hydrogen, there are about 16 grams of oxygen in water, maintaining that 1:8 ratio.
The balanced chemical equation for the reaction of hydrogen and oxygen to form water is 2H2 + O2 -> 2H2O. Based on the equation, for every 2 grams of hydrogen, 64 grams of oxygen are needed to form 36 grams of water. Thus, if 8 grams of hydrogen react completely with 64 grams of oxygen, the total mass of water formed would be 36 grams.
It is not measured in grams but PPM because it is a gas.
25
800 g oxygen are needed.
43.2 grams of water