0
How many grams of water are needed to react with 0.373 mol of ethylene?
Wiki User
∙ 10y ago
I can't
Wiki User
∙ 10y ago
To react with 0.373 mol of ethylene (C2H4), you need an equal number of moles of water (H2O) based on the balanced chemical equation:
C2H4 + H2O → C2H5OH
This means you need 0.373 mol of water to react with 0.373 mol of ethylene. To convert moles to grams, you would multiply 0.373 mol by the molar mass of water (18.015 g/mol) to get the grams needed.
Add your answer:
Earn +20 pts
How many grams of ethylene as needed to react with 0.0126 mole of water?
To determine the grams of ethylene needed to react with 0.0126 mole of water, you need to use the balanced chemical equation for the reaction between ethylene and water. Once you have the balanced equation, use the molar ratio between ethylene and water to convert moles of water to moles of ethylene. Then, use the molar mass of ethylene to convert moles of ethylene to grams of ethylene.
How many grams of H2O are needed to react with 3.5 moles of ethylene?
63 g of water are needed.
What mass in grams of ethylene oxide is needed to react with 10 g of water?
To calculate the mass of ethylene oxide needed to react with 10 g of water, you need to determine the molar ratio of water to ethylene oxide in the balanced chemical equation for the reaction. Once you have the molar ratio, you can use it to calculate the mass of ethylene oxide needed. The molar mass of ethylene oxide is 44.05 g/mol.
How many grams of water are needed to react with 79.0 CaCN2?
To determine the amount of water needed to react with 79.0 CaCN2, you need to use stoichiometry. The balanced chemical equation for the reaction is: CaCN2 + 3H2O -> CaCO3 + 2NH3 From the equation, you can see that 3 moles of water are needed to react with 1 mole of CaCN2. Calculate the moles of CaCN2 in 79.0 grams, then use the mole ratio to determine the moles of water needed. Finally, convert the moles of water to grams using the molar mass of water.
How many grams of water are needed to react with 77.0?
Not enough information was provided. Can you please provide the rest of the information so that we may calculate the answer for you?
How many grams of ethylene as needed to react with 0.0126 mole of water?
To determine the grams of ethylene needed to react with 0.0126 mole of water, you need to use the balanced chemical equation for the reaction between ethylene and water. Once you have the balanced equation, use the molar ratio between ethylene and water to convert moles of water to moles of ethylene. Then, use the molar mass of ethylene to convert moles of ethylene to grams of ethylene.
What mass in grams of ethylene oxide is needed to react with 10 g of water?
To calculate the mass of ethylene oxide needed to react with 10 g of water, you need to determine the molar ratio of water to ethylene oxide in the balanced chemical equation for the reaction. Once you have the molar ratio, you can use it to calculate the mass of ethylene oxide needed. The molar mass of ethylene oxide is 44.05 g/mol.
How many grams of H2O are needed to react with 3.5 moles of ethylene?
63 g of water are needed.
How many grams of water are needed to react with 73.0 g CaCN2?
mass H2O =49.2g
If you start with 45 grams of ethylene how many grams of carbon dioxide will be produced?
If ethylene (C2H4) undergoes complete combustion, it will react with oxygen to produce carbon dioxide and water. The balanced chemical equation for the combustion of ethylene is: C2H4 + 3 O2 → 2 CO2 + 2 H2O. Since 1 mol of C2H4 produces 2 mol of CO2, the molar ratio is 1:2. Therefore, starting with 45 grams of ethylene, it will result in 120 grams of carbon dioxide being produced.
If 44 grams of carbon react completely with 18 grams of water what is the mass of carbonic acid formed?
The molecular formula for carbonic acid is H2CO3. To find the mass of carbonic acid formed, first calculate the moles of carbon and water. Then, determine the limiting reactant and use it to calculate the moles of carbonic acid formed. Finally, convert the moles of carbonic acid to grams to find the mass.
How many gram of water are needed to react with gram of 2.72 grams Li2O given Li2O H2O2LiOH?
The molar mass of Li2O is 29.88 g/mol and the molar mass of H2O is 18.02 g/mol. Using stoichiometry, we find that 2.72 grams of Li2O requires 2.72 grams of water to react in a 1:1 ratio based on the balanced chemical equation.
How many liters of water are needed to react with 2L of oxygen to make water?
Water does not need to react with oxygen to make water!
How many moles of nitrogen dioxide are needed to react with 5.0 moles of water?
10 moles of nitrogen dioxide are needed to react with 5,0 moles of water.
How many grams of ethylene glycol automobile antifreeze C2H6O2 dissolved in 3.80kg of water is needed to lower the freezing point of water in an automobile radiator to 21.0C?
To calculate the molality needed to lower the freezing point of water to 21°C, use the formula ΔT = Kf * m, where Kf for water is 1.86°C/m. Rearrange to find molality m = ΔT / Kf = (0°C - 21°C) / 1.86°C/m = -21°C / 1.86°C/m = -11.29 m. Convert m to mol/kg: -11.29 m * 1000g water / 18.015g water = -627.72 mol/kg. Multiply by molar mass of ethylene glycol to get grams: -627.72 mol/kg * 62.07 g/mol = -38952.09 grams.
Why ethylene dissolved in water?
Because water is used as a catalyst in preparation of other product of ethylene
What mass of water is needed to react with 32.9 Li3N?
To determine the mass of water needed to react with 32.9 g of Li₃N, we first need to balance the chemical equation for the reaction between Li₃N and water. The balanced equation is: 2Li₃N + 3H₂O → 6LiOH + NH₃ From the equation, we see that 3 moles of water are needed to react with 2 moles of Li₃N. So, first calculate the moles of Li₃N in 32.9 g, then use the mole ratio from the balanced equation to find the moles of water needed, and finally convert the moles of water to grams.
