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How many grams of ethylene as needed to react with 0.0126 mole of water?
To determine the grams of ethylene needed to react with 0.0126 mole of water, you need to use the balanced chemical equation for the reaction between ethylene and water. Once you have the balanced equation, use the molar ratio between ethylene and water to convert moles of water to moles of ethylene. Then, use the molar mass of ethylene to convert moles of ethylene to grams of ethylene.
How many grams of H2O are needed to react with 3.5 moles of ethylene?
63 g of water are needed.
What mass in grams of ethylene oxide is needed to react with 10 g of water?
To calculate the mass of ethylene oxide needed to react with 10 g of water, you need to determine the molar ratio of water to ethylene oxide in the balanced chemical equation for the reaction. Once you have the molar ratio, you can use it to calculate the mass of ethylene oxide needed. The molar mass of ethylene oxide is 44.05 g/mol.
What mass in grams of ethylene oxide is needed to react with 19g of water?
To determine the mass of ethylene oxide needed to react with 19 g of water, we first need to know the balanced chemical equation for the reaction between ethylene oxide (C2H4O) and water (H2O). Typically, ethylene oxide reacts with water to form ethylene glycol. The molar mass of water is approximately 18 g/mol. Since the reaction between ethylene oxide and water is a 1:1 molar ratio, 19 g of water requires 19 g of ethylene oxide to react completely, assuming you have enough ethylene oxide available.
How many grams of water are needed to react with 79.0 CaCN2?
To determine the amount of water needed to react with 79.0 CaCN2, you need to use stoichiometry. The balanced chemical equation for the reaction is: CaCN2 + 3H2O -> CaCO3 + 2NH3 From the equation, you can see that 3 moles of water are needed to react with 1 mole of CaCN2. Calculate the moles of CaCN2 in 79.0 grams, then use the mole ratio to determine the moles of water needed. Finally, convert the moles of water to grams using the molar mass of water.
How many grams of ethylene as needed to react with 0.0126 mole of water?
To determine the grams of ethylene needed to react with 0.0126 mole of water, you need to use the balanced chemical equation for the reaction between ethylene and water. Once you have the balanced equation, use the molar ratio between ethylene and water to convert moles of water to moles of ethylene. Then, use the molar mass of ethylene to convert moles of ethylene to grams of ethylene.
How many grams of H2O are needed to react with 3.5 moles of ethylene?
63 g of water are needed.
What mass in grams of ethylene oxide is needed to react with 10 g of water?
To calculate the mass of ethylene oxide needed to react with 10 g of water, you need to determine the molar ratio of water to ethylene oxide in the balanced chemical equation for the reaction. Once you have the molar ratio, you can use it to calculate the mass of ethylene oxide needed. The molar mass of ethylene oxide is 44.05 g/mol.
What mass in grams of ethylene oxide is needed to react with 19g of water?
To determine the mass of ethylene oxide needed to react with 19 g of water, we first need to know the balanced chemical equation for the reaction between ethylene oxide (C2H4O) and water (H2O). Typically, ethylene oxide reacts with water to form ethylene glycol. The molar mass of water is approximately 18 g/mol. Since the reaction between ethylene oxide and water is a 1:1 molar ratio, 19 g of water requires 19 g of ethylene oxide to react completely, assuming you have enough ethylene oxide available.
How many grams of ethylene are needed to react with 0.132 mol of H20?
C2H4 + H2O --> C2H5OHReaction balanced at 1:1:1 mole of each compound, so you'll need 0.132 mol C2H4 and this is equal to:0.132 (mol C2H4) * 28 (g/mol C2H4) = 3.696 g C2H4 = 3.70 g C2H4
How many grams of water are needed to react with 79.0 CaCN2?
To determine the amount of water needed to react with 79.0 CaCN2, you need to use stoichiometry. The balanced chemical equation for the reaction is: CaCN2 + 3H2O -> CaCO3 + 2NH3 From the equation, you can see that 3 moles of water are needed to react with 1 mole of CaCN2. Calculate the moles of CaCN2 in 79.0 grams, then use the mole ratio to determine the moles of water needed. Finally, convert the moles of water to grams using the molar mass of water.
How many grams of water are needed to react with 73.0 g CaCN2?
mass H2O =49.2g
If you start with 45 grams of ethylene how many grams of carbon dioxide will be produced?
If ethylene (C2H4) undergoes complete combustion, it will react with oxygen to produce carbon dioxide and water. The balanced chemical equation for the combustion of ethylene is: C2H4 + 3 O2 → 2 CO2 + 2 H2O. Since 1 mol of C2H4 produces 2 mol of CO2, the molar ratio is 1:2. Therefore, starting with 45 grams of ethylene, it will result in 120 grams of carbon dioxide being produced.
How many grams of water are needed to react with 75.0 grams of CaCN2 in CaCN2 3H2O-CaCO3 2N3?
To determine the grams of water needed to react with 75.0 grams of calcium cyanamide (CaCN₂), we first need to know the molar mass of CaCN₂, which is approximately 80.1 g/mol. The balanced chemical reaction for the formation of CaCO₃ and other products indicates that 1 mole of CaCN₂ reacts with 3 moles of water. Therefore, with 75.0 grams of CaCN₂ (about 0.9375 moles), you would need approximately 2.81 moles of water, which is about 50.6 grams (since the molar mass of water is about 18 g/mol). Thus, around 50.6 grams of water are required for the reaction.
How many grams of water are needed to react with 77.0?
Not enough information was provided. Can you please provide the rest of the information so that we may calculate the answer for you?
What is the total mass of water formed when 8 grams of hydrogen reacts completely with 64 grams of ovygen?
The balanced chemical equation for the reaction of hydrogen and oxygen to form water is 2H2 + O2 -> 2H2O. Based on the equation, for every 2 grams of hydrogen, 64 grams of oxygen are needed to form 36 grams of water. Thus, if 8 grams of hydrogen react completely with 64 grams of oxygen, the total mass of water formed would be 36 grams.
How many gram of water are needed to react with gram of 2.72 grams Li2O given Li2O H2O2LiOH?
The molar mass of Li2O is 29.88 g/mol and the molar mass of H2O is 18.02 g/mol. Using stoichiometry, we find that 2.72 grams of Li2O requires 2.72 grams of water to react in a 1:1 ratio based on the balanced chemical equation.
