The heat required to evaporate 1 liter of water at 100 degrees Celsius is known as the latent heat of vaporization of water, which is approximately 2260 kJ/kg. Since the density of water is about 1000 kg/m³, the heat required would be around 2260 kJ.
There are approximately 173 liters in 173 kg of water, as the density of water is 1 kg/L.
One liter of water weighs approximately one kilogram, as water has a density of 1 kg/L.
latent heat
28.8kg. 1L = 1kg
The heat required to evaporate 1 liter of water at 100 degrees Celsius is known as the latent heat of vaporization of water, which is approximately 2260 kJ/kg. Since the density of water is about 1000 kg/m³, the heat required would be around 2260 kJ.
1,400 kg of water is 6,172.6 cups1,400 kg of water is 6,172.6 cups
3.785 kg
187 US gallons is approximately 578 Kg.
The density of diesel fuel is around 0.85 kg/L, so 1 liter of diesel fuel weighs approximately 0.85 kilograms.
Jet fuel is less dense than water, causing it to float on the surface. This is due to the fact that jet fuel consists of hydrocarbons that are lighter than water molecules. The difference in density between the two substances creates the floating effect.
The energy produced by the fuel can be calculated using the energy equivalence of mass via the formula E=mc^2, where E is energy, m is mass, and c is the speed of light. Given that the mass of the water produced is 1.10 x 10^-11 kg, substituting this value into the formula will provide the energy produced from the fuel.
There are approximately 173 liters in 173 kg of water, as the density of water is 1 kg/L.
73440
Using the direct variation model, you can set up a proportion: 72 kg (body weight) is to 54 kg (water weight) as 180 kg (body weight) is to x kg (water weight). Solving for x gives you 135 kg of water in a person weighing 180 kg.
1 ton = 1000 kilograms so 160 tons = 160,000 kg. Simple!
equivalent to one litre..i think about 4 cups and half of water