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What is the molarity of a solution that has 6 mol of CaCl2 in 3 kg of water?
The molarity is 2 mol/L.
What would the freezing point of water be if 3 mol of sugar were added to 1 kg of water?
-5.58 C
How much would the boiing point of water increase if 4 ml of NaCl were added to 1 kg of water?
(kb=0.51degrees celcious/(mol/kg) for water and i=2 for NaCl)
How many gram of water is equal to 2.2 mol of water?
2.2 mol water = 2.2 (mol) * 18 (g/mol) water = 39.6 (mol*g/mol) = 40 g18 g/mol = mol mass of H2O = 2*H + 1*O = (2*1 + 16) g/mol
How many grams are in 62 mole of scandium?
44.96 (g/mol Sc) * 62 (mol) = 2788 g = 2.8 kg Scandium
What is the molarity of a solution that has mol of kcl in 0.800 kg in water?
4 mol/0.800 kg
What is the molality of a solution that has 6 mol of CaCl2 in 3 kg of water?
2 m
How much would the freezing point of water decrease if 4 mol of sugar were added to 1 kg of water?
7.44 C
What is the molality solution that has 3 mol of glucose in 6 kg if water?
The molality of the solution is calculated by dividing the moles of solute by the mass of the solvent in kg. In this case, there are 3 mol of glucose in 6 kg of water. Therefore, the molality of the solution is 0.5 mol/kg.
What is the molality of a solution that has 3 mol of glucose in 6 kg of water?
The molality of the solution is 0.5 mol/kg. This is calculated by dividing the number of moles of solute (3 mol glucose) by the mass of solvent in kilograms (6 kg water).
What is the molality of a solution made by dissolving 2 mole of NaOH in 6kg of water?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kg. In this case, there are 2 moles of NaOH dissolved in 6 kg of water. Therefore, the molality would be 2 mol / 6 kg = 0.33 mol/kg.
What is the molarity of a solution that has 6 mol of CaCl2 in 3 kg of water?
The molarity is 2 mol/L.
What is the molality of a solution that has 6 mol of cacl2 in 3kg of water?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kilograms. In this case, the molality of the CaCl2 solution would be 2 mol/kg, as 6 mol of CaCl2 dissolved in 3 kg of water results in a molality of 2 mol/kg.
What is the molality of solution that has 3 mol of glucose in 6 Kg of water?
3mol/6kg
How much would the boiling point of water increase if 4 mol of NaCl were addes to 1 kg of water?
The boiling point elevation constant for water is 0.512 °C/kg/mol. When 4 mol of NaCl are added to 1 kg of water, the increase in boiling point would be 4 * 0.512 = 2.048 °C.
What is the molality of .630g of NaCl dissolved in 525g of water?
To find molality, first convert grams of NaCl to moles: 0.630g NaCl / 58.44 g/mol NaCl = 0.0108 mol NaCl. Next, calculate molality using moles of solute and mass of solvent: molality = moles of solute / kg of solvent = 0.0108 mol NaCl / 0.525 kg water = 0.0206 mol/kg.
How much would the freezing point of water decrease if 4 mole of Na Cl were added to 1 kg of water?
The freezing point depression constant for water is 1.86°C kg/mol. With 4 moles of NaCl added to 1 kg of water, the molality would be 4 mol / 1 kg = 4 m. The freezing point depression can be calculated as 1.86°C kg/mol * 4 m = 7.44°C.
