How many kilograms of chlorine are in 22 kg of each of the following chlorofluorocarbons C2F3Cl3 and CF3Cl?

Answer 1

To determine the amount of chlorine in each compound, we first need to find the molar mass of each compound. The molar mass of C2F3Cl3 is 187.38 g/mol, and the molar mass of CF3Cl is 104.46 g/mol. Next, we calculate the mass percentage of chlorine in each compound by dividing the molar mass of chlorine by the total molar mass of the compound and multiplying by 100. For C2F3Cl3, the mass percentage of chlorine is 106.47 g/mol / 187.38 g/mol * 100 = 56.81%. For CF3Cl, the mass percentage of chlorine is 35.45 g/mol / 104.46 g/mol * 100 = 33.94%. Finally, we calculate the amount of chlorine in 22 kg of each compound by multiplying the mass percentage of chlorine by the total mass of the compound. For C2F3Cl3, the amount of chlorine is 22 kg * 56.81% = 12.49 kg. For CF3Cl, the amount of chlorine is 22 kg * 33.94% = 7.47 kg.

Answer 2

First, C2F3Cl3 has a molar mass of 187.38 g/mole. So there are 117.41 moles of this compound. By ratio, then there are 352.23 moles of chlorine. Chlorine has a molar mass of 35.453 g/mole, so there are 12.488 kg of chlorine in that compound. CF3Cl has a molar mass of 104.46 g/mol = 210.61 moles. By ratio, there are an equivalent number of moles of chlorine, so there is 7.467 kg of chlorine in the second compound.

Answer 3

There are 6.816 kg of chlorine in 22 kg of C2F3Cl3, and 9.333 kg of chlorine in 22 kg of CF3Cl.