How many kilowatt hours are in 55.33 liters of propane?

Answer 1

The general reaction for combustion of Propane is:

C3H8 + 5O2------->3CO2 + 4H2O ,

The heat evolved during the reaction is about 360kJ/mol. (120*3=360, THE HEAT OF COMBUSTION OF METHANE IS 120 KJ/MOL). Now,

Given mass=55.33 liter =55.33kg=55330g,

Molar mass=12*3+8=44g/mol, so

Number of moles=55330/44=1257.5moles, now consider,

1 mole of propane gives energy=360kj=360,000J,

1257.5 moles will give energy=E=360,000*1257.5=452700000 j , or

E=452700000/3600000 kwh=125.75kwh. For more details, contact at saqibahmad81@yahoo.com

Answer 2

To convert from liters of propane to kilowatt hours, you'll need to know the energy content of propane, which is roughly 26.8 kWh per liter. Therefore, 55.33 liters of propane would contain approximately 1483.244 kWh (55.33 liters * 26.8 kWh/liter).