Ok
Um, I do know the Answer,
There are no Lone Pairs of Electrons in the Valence Shell of The Central Atom of SiCl4, because:
Si has the Number Configuration of: 2,8,4 The '4' is the number of dots, it has surrounding Si, one above Si, one under Si, one on the right side of Si, one on the left side of Si.
Cl has the Number Configuration of: 2,8,7 The '7' is the number of dots, it has surrounding Cl, you can have it in any order, i.e. one above Cl, two under Cl, two on the right side of Cl, two on the left side of Cl. But when you join SiCl4 together, and make it into a Lewis Structure, then the Central Atom is Si,
Then Si will have one Cl bonding above Si, one Cl bonding under Si, one Cl bonding on the right side of Si, one Cl bonding on the left side of Si, and now all you can see, is that Si has Four Cl, attaching, bonding to Si, and now Si doesnt have any Lone Pairs
In ClF3, there are two lone pairs of electrons on the central chlorine atom in addition to the three bonding pairs with fluorine atoms. This makes a total of five valence electrons not involved in bond formation.
there is only 1 lone pair present in BrF5 there are 7 electrons in Br valence shell from which 5 electrons went to make bond with F, while the remaining two makes a lone pair. and thus anly 1 lone pair exist in BrF5
The postulates of VSEPR (Valence Shell Electron Pair Repulsion) theory are: 1) The electron pairs in the valence shell of an atom repel each other, 2) Electron pairs around a central atom will arrange themselves to be as far apart as possible to minimize repulsion, and 3) The geometry of a molecule is determined by the number of electron pairs around the central atom.
4
The repulsion is between valence electrons.
In a tetrahedral molecule, the central atom has 0 unshared pairs of valence electrons. The central atom forms four chemical bonds with surrounding atoms, resulting in a total of 4 electron pairs around the central atom.
In ClF3, there are two lone pairs of electrons on the central chlorine atom in addition to the three bonding pairs with fluorine atoms. This makes a total of five valence electrons not involved in bond formation.
There are 3 pairs of valence electrons present on the boron atom in BF3. Boron has 3 valence electrons, and each fluorine atom provides one additional electron, giving a total of 6 valence electrons on boron.
There are 4 valence electrons on the oxygen atom in the water molecule. Oxygen has 6 valence electrons, and in a water molecule, oxygen forms 2 covalent bonds with the hydrogen atoms, sharing 2 of its valence electrons with each hydrogen atom.
The pairs of valence electrons that do not participate in bonding in a diatomic oxygen molecule are called lone pairs. These pairs of electrons are not involved in forming the double bond between the oxygen atoms in O2.
The answer is not 6 as said here before! The number of valence electrons in O2 (oxygen molecule) is: 12 valence electrons. 6 of them from each oxygen (O) atom. 4 valence electrons make up the double bond between the two oxygen atoms, and the remaining 8 valence electrons form lone pairs (non-bonding pairs) on the oxygen atoms, 2 lone pairs on each. I hope there is some help in this.
there is only 1 lone pair present in BrF5 there are 7 electrons in Br valence shell from which 5 electrons went to make bond with F, while the remaining two makes a lone pair. and thus anly 1 lone pair exist in BrF5
If an atom has five valence electrons, it will have one lone pair of electrons.
In SiCl4, silicon has no lone pairs because it forms four bonds with chlorine atoms, satisfying its octet rule.
lone pairs
The postulates of VSEPR (Valence Shell Electron Pair Repulsion) theory are: 1) The electron pairs in the valence shell of an atom repel each other, 2) Electron pairs around a central atom will arrange themselves to be as far apart as possible to minimize repulsion, and 3) The geometry of a molecule is determined by the number of electron pairs around the central atom.
In the Lewis structure of methane, there are no lone pairs of electrons on the central carbon atom, as all four valence electrons are used to form bonds with the four hydrogen atoms.