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How many mL of a 0.400 M concentrated solution must be added to water to get a more dilute solution with a total volume of 10.0 mL and a new concentration of 0.160 M?
To find the volume of 0.400 M solution to add, you can use the dilution formula C1V1 = C2V2: (0.400 M)(V1) = (0.160 M)(10.0 mL) V1 = (0.160 M)(10.0 mL) / 0.400 M V1 = 4.0 mL Therefore, 4.0 mL of the 0.400 M solution should be added to water to achieve a total volume of 10.0 mL with a concentration of 0.160 M.
How many ml of 110 M of HCl are needed to completely neutralize 54ml of 106 M of BaOH2 solution?
A concentration of 110 M or 106 M doesn't exist.
How many grams of lidocaine are in 150 ml of a 2.5 M solution?
150 mL of a 2.5 M lidocaine solution contain 87,9 g.
How many gmL are there in 1 kgm3?
There are 1 g/mL in 1 kg/m^3. This is because 1 kg/m^3 is equivalent to 1000 g/L, and since 1 L is equal to 1,000 mL, 1000 g/L is equivalent to 1 g/mL.
What is the density of the acid in a car battery if 200 mL of the acid had a mass of 240g?
density = mass / volume Given mass = 240 g = 240*10^-3 kg volume = 200 mL = 200*10^-6 m^3 Hence density = 1.2*10^3 kg/m^3 Or 1200 kg/m^3
How many mL of a 0.400 M concentrated solution must be added to water to get a more dilute solution with a total volume of 10.0 mL and a new concentration of 0.160 M?
To find the volume of 0.400 M solution to add, you can use the dilution formula C1V1 = C2V2: (0.400 M)(V1) = (0.160 M)(10.0 mL) V1 = (0.160 M)(10.0 mL) / 0.400 M V1 = 4.0 mL Therefore, 4.0 mL of the 0.400 M solution should be added to water to achieve a total volume of 10.0 mL with a concentration of 0.160 M.
How many millimeters are in a cubic meter?
1 m^3*[(1000ml)^3/(1m^3)]=1*10^9 ml^3
How many millilitre in 1 cubic meter?
1,000,000 millilitres-------------------Solution Method:-------------------1 m = 100 cm1 cm^3 = 1 mLTherefore:"a cubic metre" = 1 m * 1 m * 1 m = 100 cm * 100 cm * 100 cm1 m^3 = 1,000,000 cm^3Convert cm^3 to mL using the conversion ratio 1 mL = 1 cm^3 as follows:1,000,000 cm^3 * (1 mL / 1 cm^3) = 1,000,000 mL(Note: cm^3 cancel)We then subsitute 1,000,000 cm^3 in the original quation with 1,000,000 mL as follows:1 m^3 = 1,000,000 mL^ This means:1 cubic metre = 1,000,000 millilitres========First Answer:========They are not equivalent. One is to measure distance/length and the other is for volume.
How many liters in a cubic metre?
Look, 1cm3=1ml If you know this you can find the others such as 1m3 This is how.. 1cm3=1ml but 1m3=1000000 cm3 therefore, 1/1000000m3=1ml therefore,1m3=1000000ml i.e.1m3=1000000/1000 litre =1000 litres got it?? ====== 1 m = 100 cm 1 cm^3 = 1 mL 1 L = 1,000 mL Therefore: "a cubic metre" = 1 m * 1 m * 1 m = 100 cm * 100 cm * 100 cm 1 m^3 = 1,000,000 cm^3 (since 1 mL = 1 cm^3, we get the following) 1 m^3 = 1,000,000 cm^3 * (1 mL / 1 cm^3) (Note: cm^3 cancel) 1 m^3 = 1,000,000 mL 1 m^3 = 1,000,000 mL * (1 L / 1,000 mL) (Note: mL cancel) 1 m^3 = 1,000 L ^ This means: 1 cubic metre = 1,000 liters
How many cubic mm in 250mL?
1 m**3 = 1000L 1000 000 000 mm**3 = 1000L 1000 000 000 mm**3 = 1000 000 mL 1000 mm**3 = 1 mL 250 000 mm**3 = 250 mL
You want to make a 275.0 mL of a 0.15 M solution of HCl. How many mL of a 6.0 M solution do you need?
To calculate the volume of the 6.0 M HCl solution needed, you can use the formula M1V1 = M2V2. Plugging in the values, you get: (6.0 M)(V1) = (0.15 M)(275.0 mL). Solving for V1, you will need 5.7 mL of the 6.0 M HCl solution to make 275.0 mL of a 0.15 M solution.
How many ml of 0.10 m naoh solution are needed to neutralize 15 ml of 0.20 m h3po4 solution?
90. mL NaOH, remember there are two sig figs in this problem not one, hence the decimal point after the 90.
How many milliliter in one ton for oil?
The average density of petroleum is 800 kg/m-3 p=m/V --> V = m/p --> V= (1000kg)/(800kg/m-3) = 1.25 m3 There are 1003 cm3 per m3, and one cm3 is equal to one mL, therefore there are 1.25x106 mL per ton of oil.
How many ml of 110 M of HCl are needed to completely neutralize 54ml of 106 M of BaOH2 solution?
A concentration of 110 M or 106 M doesn't exist.
How many ml of 0.4040 m HNO3 would be needed to nuetralize 55.00 ml of 0.124m potassium hydroxide?
The answer is 16,9 mL.
How many 3 pounds in ml?
3 pounds of water is 1,360.777 ml.
How many grams of lidocaine are in 150 ml of a 2.5 M solution?
150 mL of a 2.5 M lidocaine solution contain 87,9 g.
