Wiki User
∙ 11y agoGiven the balanced equation
Kr + 3F2 --> KrF6
In order to find how many moles of F2 are needed to produce 3.0 moles of KrF6, we must convert from moles to moles (mol --> mol conversion).
3.0 mol KrF6 * 3 molecules F2 = 9.0 mol F2
--------- 1 molecule F2
Wiki User
∙ 11y agoTo produce 1 mole of K2HgI4, 2 moles of KI are required (from the formula K2HgI4 which shows a 2:1 ratio of KI to K2HgI4). Therefore, to produce 0.4 moles of K2HgI4, you would need 0.8 moles of KI (0.4 moles x 2 moles KI/1 mole K2HgI4).
800 g oxygen are needed.
Since the balanced chemical equation for the reaction is 4NH3 → 3N2, you can see that 4 moles of NH3 produce 3 moles of N2. This means that 5.0 moles of NH3 would produce 3.75 moles of N2.
2 moles of nitrogen monoxide (NO) are produced from 1 mole of oxygen (O2) according to the balanced chemical equation 2NO = N2 + O2. One mole of NO has a molar mass of 30 g, so 90 g of NO corresponds to 3 moles of NO. Therefore, 3 moles of O2 are required to produce 90 g of NO, which is equivalent to (3 moles) x (32 g/mol) = 96 g of O2.
The balanced chemical equation for the reaction between copper (Cu) and nitric acid (HNO3) is: 3Cu + 8HNO3 -> 3Cu(NO3)2 + 2NO + 4H2O According to the equation, 8 moles of HNO3 are required to react with 3 moles of Cu. Therefore, to react with 6 moles of Cu, you would need 16 moles of HNO3.
Three moles of hydrogen are required to produce one mole of ammonia according to the balanced chemical equation for the reaction of nitrogen and hydrogen to produce ammonia. Thus, 54 moles of hydrogen are required to produce 18.00 moles of ammonia.
To produce 1 mole of K2HgI4, 2 moles of KI are required (from the formula K2HgI4 which shows a 2:1 ratio of KI to K2HgI4). Therefore, to produce 0.4 moles of K2HgI4, you would need 0.8 moles of KI (0.4 moles x 2 moles KI/1 mole K2HgI4).
The balanced equation for the reaction between sulfuric acid (H2SO4) and potassium nitrate (KNO3) to produce nitric acid (HNO3) is: H2SO4 + 2KNO3 -> 2HNO3 + K2SO4 From the balanced equation, it can be seen that for every mole of sulfuric acid reacting, two moles of potassium nitrate are required to produce two moles of nitric acid. This is due to the stoichiometry of the reaction, where the coefficients in the balanced equation represent the mole ratios of the reactants and products.
The balanced chemical equation for the reaction is: 2 KOH + H2SO4 -> K2SO4 + 2 H2O From the equation, it can be seen that 2 moles of KOH react with 1 mole of H2SO4. Calculate the moles of H2SO4 (2.70 g / molar mass of H2SO4) and then use the mole ratio to find the moles of KOH required. Finally, convert the moles of KOH to mass (moles of KOH x molar mass of KOH) to get the required mass of KOH.
The balanced chemical equation for the reaction between H2 and NH3 is: 3H2 + N2 -> 2NH3 From the balanced equation, we can see that 3 moles of H2 produce 2 moles of NH3. Therefore, 1.8 moles of H2 will produce 1.2 moles of NH3.
800 g oxygen are needed.
The balanced chemical equation for the reaction between nitrogen and hydrogen to produce ammonia is: 3 H2 + N2 -> 2 NH3 From the balanced equation, we see that 1 mole of N2 produces 2 moles of NH3. Therefore, to convert 9 moles of H2 to NH3, we would need 9/3 = 3 moles of N2.
3Cu + 8HNO3 ----> 3Cu(NO3)2 + 2NO + 4H2O is the equation if it is dilute nitric acid. In concentrated nitric acid the equation is different. So 3 moles of copper produce 2 moles of NO. Therefore it requires 6 moles of copper to produce 4 moles of NO.
Since the balanced chemical equation for the reaction is 4NH3 → 3N2, you can see that 4 moles of NH3 produce 3 moles of N2. This means that 5.0 moles of NH3 would produce 3.75 moles of N2.
The balanced chemical equation for the reaction between methanol and oxygen is: 2 CH3OH + 3 O2 -> 2 CO2 + 4 H2O From the equation, 3 moles of O2 are required to react with 2 moles of CH3OH. Therefore, to react with 23.5 moles of CH3OH, you would need 35.25 moles of O2.
To determine the amount of calcium needed, you need to balance the chemical equation for the reaction between calcium and water. The equation is Ca + 2H2O → Ca(OH)2 + H2. Then, convert the mass of water to moles, use the stoichiometry of the balanced equation to find the moles of calcium required, and convert that to grams of calcium.
Three moles of nitrogen are required to produce 2 moles of ammonia according to the balanced chemical reaction for ammonia synthesis. Therefore, 27 moles of nitrogen are required to produce 18 moles of ammonia.