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How many mole of KI required to produce 0.4 moles K2HgI4?
the required equation is HgCl2+4KI>>2KCl+K2HgI4. according to stoichiometric calculations 4 moles of KI gives 1 mole of k2HgI4 THEREFORE 0.4 moles of K2HgI4 requires----- ? 0.4 moles x 4 moles/1 mole=1.6 moles therefore 1.6 moles of KI is required to produce 0.4 moles of K2HgI4
How many grams of oxygen will be required to produce 25 moles of sulfur dioxide how many grams of oxygen will be required to produce 25 moles of sulfur dioxide?
800 g oxygen are needed.
If 5.0 moles of NH3 are produce how many moles of N2 must have been used?
If 5.0 moles of NH3 are produced 2.5 moles of N2 are used.
How many grams of o2 are required to produce 90g of no?
2 moles of nitrogen monoxide (NO) are produced from 1 mole of oxygen (O2) according to the balanced chemical equation 2NO = N2 + O2. One mole of NO has a molar mass of 30 g, so 90 g of NO corresponds to 3 moles of NO. Therefore, 3 moles of O2 are required to produce 90 g of NO, which is equivalent to (3 moles) x (32 g/mol) = 96 g of O2.
How many moles of HNO3 are required to react with 6 moles of Cu?
The balanced chemical equation for the reaction between copper (Cu) and nitric acid (HNO3) is: 3Cu + 8HNO3 -> 3Cu(NO3)2 + 2NO + 4H2O According to the equation, 8 moles of HNO3 are required to react with 3 moles of Cu. Therefore, to react with 6 moles of Cu, you would need 16 moles of HNO3.
How many moles of hydrogen are required to produce 18.00 moles of ammonia?
N2 + 3H2 -> 2NH3 The stoichiometric equation (or balanced equation) for the formation of ammonia from this we can read off the mole ratio between hydrogen and ammonia; 3M H2 needed to produce 2M NH3 times each by 9 (so the ratio remains the same and 18M NH3 is formed) 27M H2 needed to produce 18M NH3
How many mole of KI required to produce 0.4 moles K2HgI4?
the required equation is HgCl2+4KI>>2KCl+K2HgI4. according to stoichiometric calculations 4 moles of KI gives 1 mole of k2HgI4 THEREFORE 0.4 moles of K2HgI4 requires----- ? 0.4 moles x 4 moles/1 mole=1.6 moles therefore 1.6 moles of KI is required to produce 0.4 moles of K2HgI4
How many moles of nh3 are produced when 1.8 moles h2 reacts?
The balanced chemical equation for the reaction between H2 and NH3 is: 3H2 + N2 -> 2NH3 From the balanced equation, we can see that 3 moles of H2 produce 2 moles of NH3. Therefore, 1.8 moles of H2 will produce 1.2 moles of NH3.
Why is one mole H2SO4 enough to react with 2 moles of nitre to produce nitric acid?
The balanced equation for the reaction between sulfuric acid (H2SO4) and potassium nitrate (KNO3) to produce nitric acid (HNO3) is: H2SO4 + 2KNO3 -> 2HNO3 + K2SO4 From the balanced equation, it can be seen that for every mole of sulfuric acid reacting, two moles of potassium nitrate are required to produce two moles of nitric acid. This is due to the stoichiometry of the reaction, where the coefficients in the balanced equation represent the mole ratios of the reactants and products.
What mass of potassium hydroxide is required to react completely with 2.70 g of sulfuric acid to produce potassium sulfate and water?
The balanced chemical equation for the reaction is: 2 KOH + H2SO4 -> K2SO4 + 2 H2O From the equation, it can be seen that 2 moles of KOH react with 1 mole of H2SO4. Calculate the moles of H2SO4 (2.70 g / molar mass of H2SO4) and then use the mole ratio to find the moles of KOH required. Finally, convert the moles of KOH to mass (moles of KOH x molar mass of KOH) to get the required mass of KOH.
How many grams of oxygen will be required to produce 25 moles of sulfur dioxide how many grams of oxygen will be required to produce 25 moles of sulfur dioxide?
800 g oxygen are needed.
How many moles of Cu must react to produce 4 moles of NO?
3Cu + 8HNO3 ----> 3Cu(NO3)2 + 2NO + 4H2O is the equation if it is dilute nitric acid. In concentrated nitric acid the equation is different. So 3 moles of copper produce 2 moles of NO. Therefore it requires 6 moles of copper to produce 4 moles of NO.
How many moles of nitrogen are required to convert 9 mol hydrogen gas to ammonia gas?
The balanced chemical equation for the reaction between nitrogen and hydrogen to produce ammonia is: 3 H2 + N2 -> 2 NH3 From the balanced equation, we see that 1 mole of N2 produces 2 moles of NH3. Therefore, to convert 9 moles of H2 to NH3, we would need 9/3 = 3 moles of N2.
If 5.0 moles of NH3 are produce how many moles of N2 must have been used?
If 5.0 moles of NH3 are produced 2.5 moles of N2 are used.
How many moles of O2 are required to react with 23.5 moles of methanol?
Balanced equation first. 2CH4O + 3O2 -> 2CO2 + 4H2O 23.5 moles methanol (3 moles O2/2 mole CH4O) = 35.3 moles oxygen needed --------------------------------------
How many grams of o2 are required to produce 90g of no?
2 moles of nitrogen monoxide (NO) are produced from 1 mole of oxygen (O2) according to the balanced chemical equation 2NO = N2 + O2. One mole of NO has a molar mass of 30 g, so 90 g of NO corresponds to 3 moles of NO. Therefore, 3 moles of O2 are required to produce 90 g of NO, which is equivalent to (3 moles) x (32 g/mol) = 96 g of O2.
How many moles of O2 must react with elemental chlorine to produce 69.1 moles of dichlorine heptoxide?
2Cl2 + 7O2 --> 2Cl2O7So for every 2 moles of dichlorine heptoxide formed, 7 moles of oxygen are reacted.69.1 moles Cl2O7 * (7 moles O2 / 2 moles Cl2O7) = 241.85 moles O2
