That depends on the conditions the CH4 is subjected to. At STP, CH4 would be a gas with 22.4 liters/mole (0.0224 m3/mole) or 44.6 moles/m3. If you have it at cryogenic temperatures and high pressures like the atmosphere of Jupiter, the density will be different.
There are 6.5 moles of CH4 in 6.5 moles of CH4. Each mole contains Avogadro's number of molecules, regardless of the substance.
It depends on temperature,pressure and volume.THese are needed to find number of moles
There are approximately 2.34 x 10^24 atoms in 7.75 moles of CH4. This can be calculated by multiplying Avogadro's number (6.022 x 10^23 atoms/mol) by the number of moles.
Methane reacts with oxygen in the following way. CH4 + 3 O2 --> CO2 + 4 H2O. If 5 moles of oxygen react with 2.8 moles of methane, only 1.67 moles of methane would be consumed because of the molar ratio 1:3. This would produce 1.67 moles of carbon dioxide and 6.67 moles of water.
That's a tricky question, because one molecule of CH4 is simply that, one atom of carbon and 4 atoms of Hydrogen. Moles are a UNIT used to transform atoms (which we cannot measure individually in the lab) into practical units such as grams (which we can measure). The moles of CH4 depend on the mass, in SI units of grams, that you have of this substance. The molecular weight of CH4 is 16 g/mol (12 for Carbon + 1 for each Hydrogen). If you WANTED 2 moles of CH4, you need to multiply this molecular weight by 2 moles to get 32 grams (the moles cancel out upon multiplication). So, 32 grams of CH4 is 2 moles of CH4.
2,8 moles is of course equivalent to 2,8 moles !Probable is a spelling error in your question.
There are 6.5 moles of CH4 in 6.5 moles of CH4. Each mole contains Avogadro's number of molecules, regardless of the substance.
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
The balanced equation for combustion of CH4 is CH4 + 2O2 ==> CO2 + 2H2OThus, one mole CH4 produces 1 mole CO21 g CH4 x 1 mole CH4/16 g = 0.0625 moles CH40.0625 moles CH4 ==> 0.0625 moles CO20.0625 moles CO2 x 44 g CO2/mole = 2.75 g CO2Thus, the answer would be that 1 grams of CH4 will produce 2.75 grams of CO2 after complete combustion.
One molecule has four H atoms.So two moles have 8 moles
It depends on temperature,pressure and volume.THese are needed to find number of moles
There are 12 atoms of hydrogen in 3 moles of CH4. CH4 consists of one carbon atom and four hydrogen atoms. Since each mole of CH4 has 4 hydrogen atoms, 3 moles would have 3 * 4 = 12 hydrogen atoms in total.
There are 0.75 moles in it.You have to devide 12 by molecular mass
There are 24 moles of hydrogen in 4 moles of CH4 because each molecule of CH4 contains 4 hydrogen atoms. Therefore, you have 24 moles x 6.022 x 10^23 atoms/mol = 1.4448 x 10^25 atoms of hydrogen.
First, determine molar mass of CH4: C:12g/mol + 4x H:1g/mol= 16g/mol Then divide by the number of grams. 64g/(16g/mol)= 4 moles of CH4
There are 67.2 grams of hydrogen in 5.60 moles of methane. Methane (CH4) has one carbon atom and four hydrogen atoms, so the molar mass of CH4 is 16 grams/mol (carbon) + 4 grams/mol (hydrogen) = 20 grams/mol. In 5.60 moles of CH4, there are 5.60 moles x 4 mol of hydrogen/mol of CH4 = 22.4 moles of hydrogen. Finally, converting moles to grams, 22.4 moles x 1 gram/mol = 67.2 grams of hydrogen.
For the reaction CO2 + 4H2 -> CH4 + 2H2O, the stoichiometry shows that 1 mole of CO2 produces 1 mole of CH4. Therefore, 25.1 moles of CO2 would produce 25.1 moles of CH4.