Wiki User
∙ 11y agoGiven the balanced equation
2C3H8O + 9O2 --> 6CO2 + 8H2O
To find the number of moles CO2 that will be produced from 0.33 mol C3H8O, we must convert from moles to moles (mol --> mol conversion).
0.33 mol C3H8O * 6 molecules CO2 = 0.99 mol CO2
---------- 2 molecules C3H8O
Wiki User
∙ 11y agoThe balanced equation for the combustion of isopropyl alcohol is: C3H8O + 5O2 → 3CO2 + 4H2O. The mole ratios that can be derived from this equation are: C3H8O to O2 is 1:5, C3H8O to CO2 is 1:3, C3H8O to H2O is 1:4, O2 to CO2 is 5:3, O2 to H2O is 5:4, CO2 to H2O is 3:4.
To determine the limiting reactant, first convert the masses of both reactants to moles using their molar masses. Then, calculate the moles of products that can be formed from each reactant assuming complete reaction. The reactant that produces the lesser amount of product is the limiting reactant.
2(c3h8o)+9o2 => 8h2o+6co2
The chemical symbol for isopropyl alcohol is C3H8O.
The chemical equation for isopropanol, also known as isopropyl alcohol, is C3H8O or CH3CHOHCH3. It is a colorless, flammable chemical compound commonly used as a solvent, cleaning agent, or disinfectant.
Carbon dioxide and Water are produced The chemical equation for it is C3H8O + O2 = CO2 + H2O Balance form (if needed) is: 2C3H8O + 9O2 = 6CO2 + 8H2O
To find the grams of H2O and C3H6 formed from 6g of C3H8O, first calculate the molar mass of C3H8O: 44.1 g/mol. Then, using the stoichiometry of the reaction yielding H2O and C3H6 from C3H8O, you can determine the grams produced. The balanced reaction is C3H8O -> H2O + C3H6, and for every 1 mol of C3H8O, you get 1 mol of H2O and 1 mol of C3H6. So, 6g of C3H8O yields 6g of H2O and 6g of C3H6.
That's correct! When isopropanol burns in oxygen, it undergoes combustion to produce carbon dioxide, water, and heat as products.
Dipropyl ether
The chemical reaction of isopropyl alcohol (C3H8O) with oxygen (O2) typically produces carbon dioxide (CO2) and water (H2O) as products in the presence of a heat source. The balanced chemical equation for this combustion reaction is 2C3H8O + 9O2 -> 6CO2 + 8H2O.
Complete combustion of propanol: C3H7OH + 9/2 O2 -> 3 CO2 + 4 H2O Incomplete combustion of propanol: C3H7OH + 6 O2 -> 3 CO + 4 H2O
C3H8O ==== Count them.
C3H8O ==== Count them.
The balanced equation for the combustion of isopropyl alcohol is: C3H8O + 5O2 → 3CO2 + 4H2O. The mole ratios that can be derived from this equation are: C3H8O to O2 is 1:5, C3H8O to CO2 is 1:3, C3H8O to H2O is 1:4, O2 to CO2 is 5:3, O2 to H2O is 5:4, CO2 to H2O is 3:4.
To determine the limiting reactant, first convert the masses of both reactants to moles using their molar masses. Then, calculate the moles of products that can be formed from each reactant assuming complete reaction. The reactant that produces the lesser amount of product is the limiting reactant.
2(c3h8o)+9o2 => 8h2o+6co2
200 molecules C3H8O (1 mole C3H8O/6.022 X 10^23)(3 mole C/1 mole C3H8O)(6.022 X 10^23/1 mole C) = 600 molecules of carbon atoms -------------------------------------------- Of course, you can just look at this set up and see there are 600 molecules. My answer set up is a formal set up. ( 200 * 3 would do it )