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∙ 12y agoSince the given reaction is already balanced, simply divide 12 by the coefficient of Na in the equation, resulting in a quotient of 6. Multiply the coefficients of the original equation by 6 to obtain the answer: 6 X 2 = 12 moles of water required.
(Note that the equation should have been written with mostly capital letters as follows: 2 Na + 2 H2O -> 2 NaOH + H2.)
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∙ 12y agoFor every mole of Na consumed, 1 mole of H2O is needed according to the balanced equation provided. Therefore, 12 moles of Na would require 12 moles of H2O.
I assume you mean this reaction. Zn + 2HCl --> ZnCl2 + H2 2.3 moles zinc (2 moles HCl/1 mole Zn) = 4.6 moles hydrochloric acid needed ========================
Al+HCl===> AlCl3+H2 Is the reaction. You need &.2 moles of HCl.
11 g hydrogen are needed.
2 moles of Na are needed to make 4 moles of H2, based on the balanced chemical equation for the reaction between Na and H2.
Since the reaction between hydrogen and carbon dioxide to produce water involves the same number of moles of each reactant, the number of moles of hydrogen needed would also be 30.6 moles.
I assume you mean this reaction. Zn + 2HCl --> ZnCl2 + H2 2.3 moles zinc (2 moles HCl/1 mole Zn) = 4.6 moles hydrochloric acid needed ========================
Al+HCl===> AlCl3+H2 Is the reaction. You need &.2 moles of HCl.
1,5665 moles barium phosphate
11 g hydrogen are needed.
How many moles of C are needed to react with 0.490 mole SO2?
The balanced equation for the reaction is: 3H2 + N2 -> 2NH3 From the balanced equation, we can see that 3 moles of hydrogen are needed to react completely with 1 mole of nitrogen. So if there are 3 moles of nitrogen, you would need 9 moles of hydrogen to react completely.
To find the number of moles of hydrogen gas, we first need to calculate the number of moles of chlorine gas using the ideal gas law formula (PV = nRT). Once we have the moles of chlorine gas, we can determine the moles of hydrogen gas needed for the reaction. In this case, the stoichiometry of the reaction states that 1 mole of chlorine gas reacts with 1 mole of hydrogen gas, so the required moles of hydrogen gas will be equal to the moles of chlorine gas.
For every mole of ammonia produced, we need one mole of nitrogen and three moles of hydrogen. Therefore, to produce 10 moles of ammonia, we would need: 10 moles of nitrogen 30 moles of hydrogen
2 moles of Na are needed to make 4 moles of H2, based on the balanced chemical equation for the reaction between Na and H2.
For the reaction: N2 + 3H2 -> 2NH3, you need 3 moles of hydrogen for every 2 moles of ammonia produced. Therefore, to produce 6.0 moles of ammonia, you would need 9.0 moles of hydrogen.
In the reaction between nitrogen and hydrogen, N2(g) + 3H2(g) → 2NH3(g), three moles of H2 bonds are broken for every one mole of N2 reacted.
If the reaction is not specified, we can't determine the exact moles of NO formed from NO2 based on this information alone. The reaction and stoichiometry are needed to calculate the moles of NO produced from 8.44 moles of NO2.