Since the given reaction is already balanced, simply divide 12 by the coefficient of Na in the equation, resulting in a quotient of 6. Multiply the coefficients of the original equation by 6 to obtain the answer: 6 X 2 = 12 moles of water required.
(Note that the equation should have been written with mostly capital letters as follows: 2 Na + 2 H2O -> 2 NaOH + H2.)
I assume you mean this reaction. Zn + 2HCl --> ZnCl2 + H2 2.3 moles zinc (2 moles HCl/1 mole Zn) = 4.6 moles hydrochloric acid needed ========================
Al+HCl===> AlCl3+H2 Is the reaction. You need &.2 moles of HCl.
11 g hydrogen are needed.
To determine how many moles of O2 are consumed when 309 moles of FeCr2O7 react, we first need the balanced chemical equation for the reaction. Assuming FeCr2O7 decomposes to yield Fe, Cr, and O2, a typical reaction could produce 3 moles of O2 for every mole of FeCr2O7. If this is the case, 309 moles of FeCr2O7 would consume 3 × 309 = 927 moles of O2.
It depends on what you are reacting the sodium with to generate hydrogen gas. The question is incomplete and cannot be answered as it is written
I assume you mean this reaction. Zn + 2HCl --> ZnCl2 + H2 2.3 moles zinc (2 moles HCl/1 mole Zn) = 4.6 moles hydrochloric acid needed ========================
To determine the limiting reactant, you must compare the moles of each reactant to the stoichiometry of the reaction. The balanced equation is essential to determine the ratio of moles needed for the reaction. In this case, 3.00 moles of calcium and 8.00 moles of water are given, and you can find which reactant limits the reaction by finding out which reactant would require more moles for complete reaction based on the stoichiometry.
If the reaction is not specified, we can't determine the exact moles of NO formed from NO2 based on this information alone. The reaction and stoichiometry are needed to calculate the moles of NO produced from 8.44 moles of NO2.
Ba3(PO4) is an incorrect formula. Barium phosphate has the formula 'Ba3(PO4)2 '. So write down the BALANCED reaction eq'n. 2Na3PO4 + 3Ba(NO3)2 = 6NaNO3 + Ba3(PO4)2 The molar ratios are 2:3 :: 6:1 We have 3.25 mol(Na3PO4) equivalent to '2' & 7.03 mol(Ba(NO3)2 ) equivalent to '3' We now must find the limiting reactant. So 3..25 / 2 = 1.625 & 7.03/3 = 2.34333.... We only need 1.625 moles(Na3PO4) to react with 7.03 moles (Ba(NO3)2). So at 3.25 moles the sodium phosphate is in excess. Therefore 7.03 moles barium nitrate is the limiting reactant. By equivalence 3:1 ;; 7.03 : x Hence x /1 = 7.03 / 3 x = 7.03 x 1 / 3 x = 2.34333... moles(Ba(NO3)2) is produced.
Al+HCl===> AlCl3+H2 Is the reaction. You need &.2 moles of HCl.
11 g hydrogen are needed.
How many moles of C are needed to react with 0.490 mole SO2?
The balanced chemical equation for the reaction between sodium and water is: 2 Na + 2 H2O -> 2 NaOH + H2 Since 2 moles of water are needed to react with 2 moles of sodium, 1 mole of water is needed to react with 1 mole of sodium. Therefore, 2.5 moles of sodium will require 2.5 moles of water for the reaction.
The balanced equation for the reaction is: 3H2 + N2 -> 2NH3 From the balanced equation, we can see that 3 moles of hydrogen are needed to react completely with 1 mole of nitrogen. So if there are 3 moles of nitrogen, you would need 9 moles of hydrogen to react completely.
To find the number of moles of hydrogen gas, we first need to calculate the number of moles of chlorine gas using the ideal gas law formula (PV = nRT). Once we have the moles of chlorine gas, we can determine the moles of hydrogen gas needed for the reaction. In this case, the stoichiometry of the reaction states that 1 mole of chlorine gas reacts with 1 mole of hydrogen gas, so the required moles of hydrogen gas will be equal to the moles of chlorine gas.
To determine how many moles of O2 are consumed when 309 moles of FeCr2O7 react, we first need the balanced chemical equation for the reaction. Assuming FeCr2O7 decomposes to yield Fe, Cr, and O2, a typical reaction could produce 3 moles of O2 for every mole of FeCr2O7. If this is the case, 309 moles of FeCr2O7 would consume 3 × 309 = 927 moles of O2.
This is based on calculations too. It contains 18 hydrogen moles.