A US Gallon of ethanol contains 3.785 liters and each liter weighs 0.789 kg. A Mole weight of ethanol is 46.06 g.
So...
Moles/gallon ethanol= (3.785 L)x(789g/L)/(46.06g/mole) = 63.84
Assuming you need to show how the units cancel out I've indicated what they are.
The answer is not quite correct in the real world as ethanol is produced at about 96% purity if not denatured. The 4% or so is water.
Added:
The last addition is correct and can be easily re-calculated knowing two things:
1. the density of 96% ethanol + 4% water is a bit higher: 799 g/L
2. 96% means 96% by volume (0.960 L per 1.00 Litre)
Newly calculated:
(0.960L/1.00L)(3.785 L)x(799g/L)/(46.06g/mole) = 63.03 mol ethanol in a gallon 96% alcohol
Yes they are; A pint of beer, a gallon of petrol (Gasoline)
One gallon = 128 ounces.
128 US ounces = 1 US gallon
1 US gallon = 128 fluid ounces
1 gallon = 128 fluid ounces 1/2 gallon = 64 fluid ounces
16 ounces
128 fluid ounces.
128 fl oz to a gallon of gasoline.
Yes they are; A pint of beer, a gallon of petrol (Gasoline)
It depends on the mixing ratio of gasoline / oil for the specific piece of equipment you will use the gas / oil mix. Most lawn equipment such as weed eaters and leaf blowers require a 32:1 mixture. Since 1 gallon of gasoline is 128 ounces, it is necessary to mix 128 ounces (or 1 US gallon) of gasoline to 4 ounces of 2 cycle oil to equal 32:1 ratio.
128 ounces in a gallon.
To mix oil with gasoline at a 50:1 ratio, you need 2.6 ounces of oil for every gallon of gas. This is calculated by dividing 128 ounces (the number of ounces in a gallon) by 50, which equals 2.56 ounces. Therefore, you would round it to approximately 2.6 ounces of oil per gallon of gas for a 50:1 mixture.
It is 2.56 ounces of oil to a gallon of gasoline.
One gallon = 128 ounces.
128 US ounces = 1 US gallon
1 US gallon = 128 fluid ounces
That is 1,536 ounces.