A US Gallon of ethanol contains 3.785 liters and each liter weighs 0.789 kg. A Mole weight of ethanol is 46.06 g.
So...
Moles/gallon ethanol= (3.785 L)x(789g/L)/(46.06g/mole) = 63.84
Assuming you need to show how the units cancel out I've indicated what they are.
The answer is not quite correct in the real world as ethanol is produced at about 96% purity if not denatured. The 4% or so is water.
Added:
The last addition is correct and can be easily re-calculated knowing two things:
1. the density of 96% ethanol + 4% water is a bit higher: 799 g/L
2. 96% means 96% by volume (0.960 L per 1.00 Litre)
Newly calculated:
(0.960L/1.00L)(3.785 L)x(799g/L)/(46.06g/mole) = 63.03 mol ethanol in a gallon 96% alcohol
There are 16 ounces in a pint and 128 ounces in a gallon.
There are 128 ounces in a gallon.
There are 128 ounces in a gallon.
There are 128 full ounces in a gallon.
There are 64 ounces in a gallon, so half a gallon would be 32 ounces.
16 ounces
128 fluid ounces.
128 fl oz to a gallon of gasoline.
There are 16 ounces in a pint and 128 ounces in a gallon.
It depends on the mixing ratio of gasoline / oil for the specific piece of equipment you will use the gas / oil mix. Most lawn equipment such as weed eaters and leaf blowers require a 32:1 mixture. Since 1 gallon of gasoline is 128 ounces, it is necessary to mix 128 ounces (or 1 US gallon) of gasoline to 4 ounces of 2 cycle oil to equal 32:1 ratio.
It is 2.56 ounces of oil to a gallon of gasoline.
128 ounces in a gallon.
There are 128 ounces in a gallon.
There are 128 ounces in a gallon.
There is 128 oz in a liquid gallon so to achieve a 40 to 1 ratio you would add approximately 3.2 oz of 2 cycle oil to one gallon of gasoline.
50:1
There are 128 full ounces in a gallon.