There are four significant figures in the measurement 1.050 L.
Wiki User
∙ 9y agoWiki User
∙ 13y agoThere are 2 significant figures--the two fours. Placeholder zeroes are not significant.
Wiki User
∙ 6y agoFour of them.
Wiki User
∙ 15y ago4
It already is rounded to three significant figures.
The most accurate answer is 0.2 mol/kg.Related Information:The number of significant figures in the final answer must be based on the given with the least number of significant figures which is 2L.
1042 L rounded off to two significant digits is 1000 L.
Density= mass/volume. D= 3.0g/1.0L D= 3.0g/L Make sure you write 3.0g/L and not just 3 so that you have the right number of significant figures. Also, make sure that your instructor wants the answer in g/L because density is usually measured in g/mL.
You solve this using the ideal gas law: PV = nRT and solve for n (moles)n = PV/RT = (2.62 atm)(47.8 L)/(0.0821 Latm/Kmol)(775K) n = 1.97 moles (3 significant figures)
There are 3 significant figures in this measurement.
There are 3.
There are three.
Four.
3.134
4 of them.
The answer should have three significant figures since the divisor (3.42) has three significant figures. Therefore, the result of the division, 13.3669590643 kg/L, should be rounded to three significant figures, which is 13.4 kg/L.
Significant figures are calculated using various rules.ÊAll non-zero numbers are significant and all zeros that are to the right of the decimal point as well as at the end of a number are significant.ÊTherefore, 1.050L has 4 significant figures.
98.5 L
0.0004 has one significant figure.
9
Assuming that the last 0 is not there purely to use up ink, 4 sig figs.