To determine the number of significant figures in the product of 0.1400, 6.02, and (10^{23}), we need to identify the significant figures in each number. The number 0.1400 has four significant figures, 6.02 has three significant figures, and (10^{23}) has one significant figure (as it is a power of ten). The product will have the same number of significant figures as the term with the least significant figures, which is 6.02 with three significant figures. Therefore, the final product will have three significant figures.
6.022 x 1023
1 mole C = 12.011g C 1.2g C x 1mol C/12.011g C = 0.10 mole C rounded to two significant figures
A mole is 6.022×1023 of anything, including atoms. So to determine the number of atoms are in 30 moles of iron, you multiply the number of moles times 6.022×1023. 30mol Fe x 6.022×1023 atoms Fe/1mol Fe = 1.8066×1025atoms Fe When corrected for significant figures, the answer is 2×1025atoms Fe. Note: the number following the 10 in the large numbers is the exponent on the 10 and should be written as superscripts, but that is not supported at the moment.
In one mole of any substance, there are 6.02 x 1023 constituent particles, correct to three significant figures. This is the Avogadro constant. Thus for two moles of He, there are 1.20 x 1024 atoms. (Note that He is a monatomic gas and exists as a single atom.)
1 mole Al = 6.022 x 1023 atoms Al 0.2mol Al x 6.022 x 1023 atoms Al/1mol Al = 1 x 1023 atoms Al (rounded to 1 significant figure)
6.022 x 1023
There are: (1023*24)/12 = 2046
The product of 6.02 and 1023 is 6158.46
8
2406
First, calculate the product of 1023 and 24, which is 24,552. To find how many twelves are in 24,552, divide 24,552 by 12. This gives you 2,046, indicating there are 2,046 twelves in the product of 1023 and 24.
Since the product of zero with any other number(s) is zero, there are no moles in the question as written. If 5.5 X 1023 was intended to be written instead of "5.5x0x1o23", the answer is (5.5 X 1023 )/(Avogadro's number) = 0.83 moles, to the justified number of significant digits.
1 mole C = 12.011g C 1.2g C x 1mol C/12.011g C = 0.10 mole C rounded to two significant figures
27 x 1023 = 2700000000000000000000000
A mole is 6.022×1023 of anything, including atoms. So to determine the number of atoms are in 30 moles of iron, you multiply the number of moles times 6.022×1023. 30mol Fe x 6.022×1023 atoms Fe/1mol Fe = 1.8066×1025atoms Fe When corrected for significant figures, the answer is 2×1025atoms Fe. Note: the number following the 10 in the large numbers is the exponent on the 10 and should be written as superscripts, but that is not supported at the moment.
divide the amount of particles given in the question by avagado's number to get the amount in moles. 3.01 x 1023 / 6.022 x 1023 which is about 0.5 moles. them multiply the amount of moles by the mass of Nitrogen to get it in grams. 0.5 x 14 = 7g
5.5 x 10-8