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The formula you are loking for is W = E xE/R.

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The question is a little vague, but assuming you mean that the 120 volts is measured across the portion of the circuit having the 0.5 ohm resistance, then the answer is 28,800W dissipated in that resistance. The basic formula for power dissipation is current (measured in Amperes) X electromotive force (measured in Volts). We typically write this as P = IV or sometimes P=IE, where P represents power in Watts, I represents current in Amps, and V or E represent electromotive force in Volts. In the example cited in your question, we have the voltage, but we don't have the current. Since we do know the resistance, though, we can calculate the current from ohms law, which states that the voltage will always equal the product of resistance and current. We write this as V = IR, where V and I are voltage and current as above, and R represents resistance in Ohms. We can manipulate this expression to give us the current from voltage and resistance as I = V/R. Now we plug this expression into our power expression by substituting V/R in place of I.

P = IV becomes P = (V/R)V. Which we clean up to get P = V^2/R, where V^2 means the square of the voltage.

So, using this expression for the example we get P = 120*120 / 0.5 = 28,800W. :-)

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14y ago
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4mo ago

To find the watts in a system, you can use the formula P = V x I, where P is power in watts, V is voltage in volts, and I is current in amps. For a system with 120 V and 25 A, the calculation would be 120 V x 25 A = 3000 watts.

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12y ago

How many convert 0.5 amp to my electric bill

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12y ago

power = v x I

120 X 25

3000W,

1KW=1000W SO,3000 DIVIDED BY 1000

3000/1000=3KW,IT WILL DRAW 3KW THAT 25AMP 120V CIRCUIT...

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9y ago

The answer is 120 x 12.5 watts. In practice it could be less depending on the power factor.

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9y ago

The equation that you are looking for is W = A x V.

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12y ago

3000 watts

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Q: How many watts are in a system with 120 v and 25 amps?
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