In a residence assume you are referring to 120 volt supply. Watts = amps x volts x Power Factor. Now Power factor is one for resistive loads like incandescent light bulbs. Power Factor can vary from zero to one when inductive loads like motors are added. So the maximum theoretical wattage would be about 15 A x 120 V. However, you de-rate a breaker to 80% of capacity so as not to continually trip breaker. Therefore, the answer you are looking for in a practical sense is 120 x 15 x .8 = 1440 watts or 1.44 kilowatts.
The equation that you are looking for is I = W/E. Amps = Watts / Volts.
A 20 amp breaker can handle up to 2400 watts per hour (20 amps x 120 volts = 2400 watts).
30X240=7200
At 120 volts a 15 amp breaker can be loaded to 1800 watts before it will trip. If it is a continuous load then the electrical code states that it is only allowed to be loaded to 80%. This will be 1800 x .8 = 1440 watts. If the voltage is not 120 volts use the following equation Watts = Amps x Volts. Amps being the breaker size that is to be used.
A 60 amp 2-pole breaker can handle up to 14,400 watts (60 amps x 240 volts). This is because a 2-pole breaker provides 240 volts, which is the typical voltage for larger appliances and machinery.
The equation that you are looking for is I = W/E. Amps = Watts / Volts.
A 20 amp breaker can handle up to 2400 watts per hour (20 amps x 120 volts = 2400 watts).
30X240=7200
At 120 volts a 15 amp breaker can be loaded to 1800 watts before it will trip. If it is a continuous load then the electrical code states that it is only allowed to be loaded to 80%. This will be 1800 x .8 = 1440 watts. If the voltage is not 120 volts use the following equation Watts = Amps x Volts. Amps being the breaker size that is to be used.
Should be fine if that is all that is on the breaker.
A 60 amp 2-pole breaker can handle up to 14,400 watts (60 amps x 240 volts). This is because a 2-pole breaker provides 240 volts, which is the typical voltage for larger appliances and machinery.
A 20 amp circuit breaker at 208 volts can handle up to 4160 watts (20 amps x 208 volts = 4160 watts). This is calculated by multiplying the amperage by the voltage to determine the maximum wattage capacity of the circuit.
To answer this question a voltage must be given. Watts = Amps x Volts. <<>> Answer At 115 volts ac, 30 amps equals 3,450 watts.
On a 20 amp breaker, you can safely operate devices that consume up to 2400 watts (20 amps x 120 volts = 2400 watts). Exceeding this limit can trip the breaker to prevent overheating and fire hazards.
Yes, it can.
14 gauge will handle it with a 15 amp breaker. If you use 12 gauge use a 20 amp breaker.
The maximum wattage that a 30 amp breaker can handle is 30 x 230 = 6900 watts. Other variables come into play and this number will decrease depending on the load, duty time, and difference in voltage fluctuation.