A watt is a unit of power (Joules/second: energy / time). I guess it depends on what method you are using to get energy out of the water, as to how much energy is in it.
"Watt" is a rate of moving energy. Anynumber of watts can heat your liters,but the less watts you use, the longer the job will take.
A 30-gallon electric water heater typically has a power rating of around 4500 watts. To determine the amperage, you can use the formula: amperage (A) = watts (W) / volts (V). Assuming a standard voltage of 240 volts, this would mean the heater pulls about 18.75 amps (4500 W / 240 V). However, actual amperage may vary based on the specific model and its energy efficiency.
There are 768 teaspoons of water in one gallon.
The amount of energy required to freeze water depends on the initial temperature of the water and the desired final temperature (0°C for freezing water). To calculate the power in watts needed to freeze water, you would need to know the mass of water, its initial temperature, and the time over which you want to freeze it.
Do you mean how many watts are used to make hot water? It varies, but a typical home electric hot water heater consumes about 4,500 watts. Industrial hot water heaters might use 20,000 watts or more! I have a little warmer that keeps my coffee warm as I type this, it consumes about 300 watts. Of course it only heats 6 ounces of water....
2.4705 watts/hour
0.29308323563892147 watts per btu there for 5200 btu = 1524.0328253223915 watts 1 watt=3.412Btu/hr 1 Btu=the amount of energy needed to heat 1 Lb of water 1 degree. A gallon of water weighs aprox. 8 Lbs.
1 gallon of water is 4540 cc and 1 degree F is 0.555 degrees C, so raising 4540 cc of water by 0.555 degree C would take 4540x0.555 calories, or 2520 calories. Multiply by 4.2 to convert to joules which gives 10590 joules. Therefore the energy required is 10590 joules which is the same as 10590 watt-seconds. That could be done by 100 watts in 105.9 seconds, or 1000 watts in 10.59 seconds.
"Watt" is a rate of moving energy. The more watts you use, the faster the waterwill heat up. The fewer watts you use, the slower it will heat. If you can affordthe time to wait, then any amount of power will do the job, no matter how small.
To determine how many solar panels are needed to run an 80-gallon water heater, you first need to know the wattage of the heater. An average electric water heater uses about 4,500 watts. Assuming you get around 300 watts per solar panel and about 4-5 hours of effective sunlight per day, you would need approximately 4-5 solar panels to effectively run the water heater, depending on your location and energy efficiency. Always consult with a solar energy professional for a precise assessment tailored to your specific situation.
"Watt" is a rate of moving energy. Anynumber of watts can heat your liters,but the less watts you use, the longer the job will take.
A 30-gallon electric water heater typically has a power rating of around 4500 watts. To determine the amperage, you can use the formula: amperage (A) = watts (W) / volts (V). Assuming a standard voltage of 240 volts, this would mean the heater pulls about 18.75 amps (4500 W / 240 V). However, actual amperage may vary based on the specific model and its energy efficiency.
One kilowatt is 1000 Watts.
If you have a gallon, you only can have one gallon.
To freeze 1 gallon of water, it requires approximately 144 BTUs. This is based on the latent heat of fusion, which is the energy needed to change water from liquid to solid at 32°F (0°C). Since 1 gallon of water weighs about 8.34 pounds, the total energy required includes the cooling of the water to its freezing point as well as the phase change.
There are 768 teaspoons of water in one gallon.
One gallon of water weighs about 3.783 kg