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How may Liters in a Volume of 1.20 mol of gas at 61.3kPa and 25 degrees C?
Wiki User
∙ 11y ago
48.5 L
(:
Wiki User
∙ 11y ago
The volume can be calculated using the ideal gas law equation, V = (nRT) / P, where n is the number of moles (1.20 mol), R is the gas constant (8.31 LkPa/molK), T is the temperature in Kelvin (25 + 273 = 298 K), and P is the pressure (61.3 kPa). Substituting these values into the equation gives V = (1.20 mol * 8.31 LkPa/molK * 298 K) / 61.3 kPa ≈ 49.1 L.
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