I'm going to assume that you mean 23.34g of NaCl.
1 mole NaCl = 58.442g NaCl (the atomic weight of Na and Cl in grams)
23.34g NaCl x (1mol NaCl/58.442g NaCl) = 0.3994mol NaCl
There are 1.946 moles of NaCl in 1.946 moles of NaCl. Each mole of NaCl contains Avogadro's number of molecules, which is approximately 6.022 x 10^23.
To find the number of moles in 737g of NaCl, first calculate the molar mass of NaCl, which is 58.44 g/mol. Then divide the given mass (737g) by the molar mass to get the number of moles. Number of moles = 737g / 58.44 g/mol ≈ 12.61 moles of NaCl.
Find moles NaCl first.14.60 grams NaCl (1 mole NaCl/58.44 grams)= 0.2498 moles NaCl================Now,Molarity = moles of solute/Liters of solutionMolarity = 0.2498 moles NaCl/2.000 Liters= 0.1249 M NaCl solution--------------------------------
1.946 moles NaCl (58.44 grams/1 mole NaCl) = 113.7 grams sodium chloride ======================
To calculate the number of moles in 23.34 g of NaCl, you first need to determine the molar mass of NaCl, which is approximately 58.44 g/mol. Then, you divide the mass given by the molar mass to find the number of moles. In this case, 23.34 g divided by 58.44 g/mol equals approximately 0.4 moles of NaCl.
The answer is 0,96 moles.
To determine the number of moles of NaCl, you need to know the mass of NaCl you have and the molar mass of NaCl (58.44 g/mol). You can then use the formula moles = mass / molar mass to calculate the number of moles of NaCl.
Molarity = moles of solute/liters of solution ( 50 ml = 0.05 liters ) 2.50 Molar NaCl = moles NaCl/0.05 liters solution = 0.125 moles NaCl ( 7.305 grams NaCl )
There are 1.946 moles of NaCl in 1.946 moles of NaCl. Each mole of NaCl contains Avogadro's number of molecules, which is approximately 6.022 x 10^23.
There are 2 moles of sodium for every 1 mole of NaCl, so in 4.0 moles of NaCl, there are 8.0 moles of sodium.
To find the number of moles in 737g of NaCl, first calculate the molar mass of NaCl, which is 58.44 g/mol. Then divide the given mass (737g) by the molar mass to get the number of moles. Number of moles = 737g / 58.44 g/mol ≈ 12.61 moles of NaCl.
Molarity = moles of solute/Liters of solution ( 300 ml = 0.300 Liters ) For our purposes, Moles of solute = Liters of solution * Molarity Moles NaCl = 0.300 Liters * 0.15 M = 0.05 moles NaCl =============
1 mole of NaCl: Na = 1 * 22.99 g = 22.99 g Cl = 1* 35.45 g = 35.45 g Total = 58.44 g 238 g NaCl * (1 mol NaCl/58.44 g NaCl) = 4.07 mol NaCl There are approximately 4.1 moles in 238 grams of sodium chloride.
To find the grams in 6.20 moles of NaCl, you need to multiply the number of moles by the molar mass of NaCl. The molar mass of NaCl is 58.44 g/mol. Therefore, 6.20 moles of NaCl is equal to 362.49 grams.
If 2 moles of Na2CrO4 react completely, they will form the same number of moles of NaCl. This is because the mole ratio between Na2CrO4 and NaCl is 1:2. Therefore, 2 moles of Na2CrO4 will form 2 moles of NaCl.
This depends on the mass of NaCl.
To find the grams of NaCl with 2.34 moles of Cl2, you need to consider the molar ratio. For every 1 mole of Cl2, there are 2 moles of Cl in NaCl. So, 2.34 moles of Cl2 would be equivalent to 4.68 moles of Cl in NaCl. Using the molar mass of NaCl (58.44 g/mol), you can calculate that 4.68 moles of NaCl would be approximately 273.64 grams.