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How many moles are in 1.946 moles of NaCl?
There are 1.946 moles of NaCl in 1.946 moles of NaCl. Each mole of NaCl contains Avogadro's number of molecules, which is approximately 6.022 x 10^23.
How many moles of NaCl are in 737 g of NaCl?
To find the number of moles in 737g of NaCl, first calculate the molar mass of NaCl, which is 58.44 g/mol. Then divide the given mass (737g) by the molar mass to get the number of moles. Number of moles = 737g / 58.44 g/mol ≈ 12.61 moles of NaCl.
What is the molarity of a 2.000 L solution thatis made from 14.60 g of NaCL?
Find moles NaCl first.14.60 grams NaCl (1 mole NaCl/58.44 grams)= 0.2498 moles NaCl================Now,Molarity = moles of solute/Liters of solutionMolarity = 0.2498 moles NaCl/2.000 Liters= 0.1249 M NaCl solution--------------------------------
How may grams are in 1.946 moles of NaCl?
1.946 moles NaCl (58.44 grams/1 mole NaCl) = 113.7 grams sodium chloride ======================
How many moles are in 23.34 g of NaCl?
To calculate the number of moles in 23.34 g of NaCl, you first need to determine the molar mass of NaCl, which is approximately 58.44 g/mol. Then, you divide the mass given by the molar mass to find the number of moles. In this case, 23.34 g divided by 58.44 g/mol equals approximately 0.4 moles of NaCl.
