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How much heat is released as 5 grams of water vapor cools from 150 degrees celsius to 105 degrees celsius?
Wiki User
∙ 14y ago
Q = mc(dT) where dT = the change in temperature of the substance.
Knowing that the specific heat of water (c) is 4.186 J/g C and that m = 5g we can find the solution.
Q = (5g)(4.186 J/g C)(150-105)C
Q = 941.85 J
Wiki User
∙ 14y ago
To calculate the heat released when 5 grams of water vapor cools from 150°C to 105°C, you need to use the specific heat capacity of water. The formula to calculate heat released is: Q = m * c * ΔT, where Q is the heat released, m is the mass of the substance, c is the specific heat capacity of water, and ΔT is the change in temperature. Substituting the values, you can calculate the heat released.
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