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You can only reduce amperage in a circut by reducing the number or size of devices plugged in to it. To make it easy, imagine you have a 120watt light bulb. Given your household voltage is normally 120v this would draw 1 amp, (volts X watts = amps). fifteen of these bulbs would draw 15 amps, the size of a commonly used circut breaker. The sixteenth light bulb added to the circut should trip the circut breaker or fuse to protect the wiring from overheating. If you chose to use 60watt bulbs instead you should be able to burn 30 of them before th breaker trips. Likewise if you needed 240watt bulbs, that same circut could only carry 7 of them.
To lower amps in a circuit, you can use a resistor to limit the current flow. By adding a resistor with the appropriate resistance value, you can decrease the amperage in the circuit. Make sure to choose a resistor with the correct power rating to avoid overheating.
the current flowing in the circuit can be reduced by simply adding a shunt resistance
in parallel with the circuit , the shunt resistance must have much lower value than the resistance of the circuit
In order to reduce the electrical current flow there must be more resistance to the flow of electrons. In an AC Circuit the resistance can come from a resistor, capacitor or inductor.
AnswerIn general, you can do this by reducing the load. However, for a load with a poor power-factor (e.g. motor loads), power-factor improvement will reduce the load current. This is achieved by placing capacitors, of appropriate value, across the load.
The answer to this depends on what is your reason for asking.
If there is too much current on the circuit and your breaker is tripping then the only answer is to reduce the load; in other words, unplug things from the circuit until you get to safe current levels.
If you think there should be more current than what you have measured, there is likely a problem with the wiring. It may be an excessively long run of wire causing a significant voltage drop or it may be a loose connection somewhere. If it is a loose connection, it will pose a fire hazard. If it is an excessively long run of wire, you may damage your devices by providing lower than standard voltage levels.
There is only one way to lower amps, is to put more resistance in the circuit but that will mean loss of power
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Will a 7000 starting amps and 10500 running amps run a 78 amp furnace?
In the electrical trade the only time there is a reference to start and running amps is when dealing with motors. The running amps is always lower than the starting amps. A 78 amp electric furnace will take a 100 amp service for it to operate and be within the electrical code guide lines.
Why is it that the thicker copper wire the more amps produced?
A wire does not produce amps. A wire with a larger cross sectional area allows more amperage to pass through it with less voltage drop due to a lower resistance.
200ma in amps?
200ma is .200 amps or .2 amps
How much does a basic home freezer pull in amps?
A basic home freezer typically pulls around 1-2 amps when running. It may draw slightly more when starting up, but it settles to a lower continuous operating amperage.
How do you convert HV amps to LV amps?
To convert high voltage (HV) amps to low voltage (LV) amps, you can use the formula: HV amps = LV amps x (LV voltage / HV voltage). By rearranging the formula, you can calculate LV amps by dividing HV amps by the ratio of HV voltage to LV voltage.
Can you use a different brand charger with a lower voltage and a hr?
Lower voltage, no, lower amps, yes. I will just take longer to charge the battery.
What amp do you charge ATV battery?
you charge a atv battery at 2 amps or lower
Does a lower impedance increases or decreases the short circuit amps available at the terminals of transformers?
Increases
What does the symbol for micro amps look like?
A lower case u with a tail infront of it and an uppercase A
What is the symbol for micro amps?
A lower-case Greek letter 'mu', followed, without a space, by an upper-case A. Incidentally, when written in full, it's 'microamperes', not 'micro amps'!
Why is my single phase induction motor drawing to many amps?
I have a single phase induction motor. It draws 8 amps on start up and climbs to 14-15 amps when I put a load on it. When I don't have a load it runs at 1 and climbs to 2-3 amps. It is normal operation for this motor to run at the lower number of amps with a load. But I don't know what is wrong.
Will a 7000 starting amps and 10500 running amps run a 78 amp furnace?
In the electrical trade the only time there is a reference to start and running amps is when dealing with motors. The running amps is always lower than the starting amps. A 78 amp electric furnace will take a 100 amp service for it to operate and be within the electrical code guide lines.
What is Full Load Amps?
FLA is the nameplate amperage rating of the motor when it is running at its designed horsepower and on the motors designed voltage. 746 watts = 1 HP. The FLA of a 1 HP motor at 240 volts would be W = amps x volts, Amps = Watts/Voltage. 746/240 = 3.1 amps full load. Overload the motor and the amps go higher, motor running at no load amps are lower than FLA
Can you use a van battery with higer amps in a car that had a battery with lower amps?
Yes, there is really no van battery or car battery. There is just an automotive battery. Installing a battery with more Cold Cranking Amps (CCA) is fine and will just provide more power in cold temperatures.
Do resistors lower volts or amps?
Current is directly proportional to the applied emf (voltage) and inversely proportional to the resistance of the circuit.
Why is it that the thicker copper wire the more amps produced?
A wire does not produce amps. A wire with a larger cross sectional area allows more amperage to pass through it with less voltage drop due to a lower resistance.
What is the advantage of 1 amps current transformer than that of the old type 5 amps current transformer?
If the protection relay and CT installed for away, then it is advised to install 1A CT rather than 5A CT. Because of lower amps it will reduce the losses on the cable. p = i^2.R
