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C2H6 + O2 = CO2 + H2O

There are two carbons in the reactant, so there are two carbon in 'CO2', by writing '2CO2' .

Hence

C2H6 + O2 = 2CO2 + H2O

Similarly, there are six hydrogen in the reactant, so there are six hundreds in H2O , by writing ' 3H2O .

Hence

C2H6 + O2 = 2CO2 + 3H2O

To balance the oxygens, we now think ' backwards'.

We note in the products there are 2 x 2 = 4 oxygen in CO2. and 3 x 1 = 3 in H2O. So we need 4 + 3 = 7 oxygens in the reactants. We already have '2' oxygen in the reactants as 'O2' . To make this up to '7' , we write ' 3 1/2' as the molar ratio/. ( 2 x 3 1/2 = 7)

Hence C2H6 + ( 3 1/2)O2 = 2CO2 + 3H2O

Chemists do NOT like fractions in the molar ratios. So to remove the '3 1/2' we multiply the whole reaction eq'n by '2'.

Hence

2C2H6 + 7O2 = 4CO2 + 6H2O is the balanced reaction eq'n.

NB Note the number of each type of atom are equal on both sides.

4 carbons

12 hydrogens

14 oxygens.

NNB When doing these combustion eq'ns for alkanes, alkenes, alkynes, etc., Think to forward balance the carbons and hydrogens, then 'Back' think of the number of oxygens.

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lenpollock

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18h ago

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