25.2 C
60
To find the volume of neon in the new conditions, we can use the combined gas law. Given initial conditions (T1 =127°C, P1 = 450 mmHg) and final conditions (T2=227°C, P2=900 mmHg), we can calculate the final volume V2 using the formula: (P1 * V1 * T2) / (T1 * P2). Plug in the values to get the final volume of neon.
1600
THE ANSWER IS 62.8 DEGREES.....
1.83
To calculate the new volume of the hydrogen gas, you can use Charles's Law, which states that the volume of a gas is directly proportional to its temperature (at constant pressure). You would first convert the temperatures to Kelvin (373 K and 473 K), then use the ratio of the initial and final temperatures to find the new volume. The new volume of the gas would be 35 liters.
60
Using the ideal gas law, (PV = nRT), we can solve for the final temperature using the initial conditions and new pressure. Rearranging the equation to solve for T, we get (T = (P2/P1) * T1), where T1 is the initial temperature. Substituting the values, we find the final temperature to be 80 degrees Celsius.
In liters, gasoline makes up about 73 liters of the final 170, diesel and heating oil make up about 40 liters, while kerosene-type jet fuels make up about 15.5 liters.
$1.20 gst was added to a $12 bill what is the final total
To find the volume of neon in the new conditions, we can use the combined gas law. Given initial conditions (T1 =127°C, P1 = 450 mmHg) and final conditions (T2=227°C, P2=900 mmHg), we can calculate the final volume V2 using the formula: (P1 * V1 * T2) / (T1 * P2). Plug in the values to get the final volume of neon.
I believe it will be 145.52 degrees Celsius if I did my math correctly. You need to convert calories to joules. I believe one joule raises the temp of 1 gram water by 1 degree Celsius so 1200*4.184=5020.8 J /40grams=125.52 temp increase+20=145.52 degrees Celsius.
In tournaments, at the end of the round it is added to the final sanctioned score.
42.3 C
1600
To find the final temperature, we can use the principle of conservation of energy: heat lost by gold = heat gained by water. We can use the formula m * c * ∆T to calculate the heat exchanged. By setting the two heat exchanges equal to each other and solving for the final temperature, we can find that the final temperature is 25.9 degrees Celsius.
Molarity = moles of solute / liters of solution. First, calculate the moles of NaOH using its molar mass. Then, divide the moles by the final volume in liters (3.00 L) to find the molarity.