If a rocket traveled at a 45 degree angle for 2.3 seconds at 1294 mph how far would it travel in total?

Answer 1

horizontal component = 915 m/h so 915*2.3=2104 miles horizontally

vertical component = 915 m/h (409m/s)

u=409m/s

t=2.3 s

a= -10 (m/s)/s

s=?

s=ut+(0.5*a*t^2)

s=(409*2.3)+(0.5*-10*2.3*2.3)

s=940.7+-26.45

=914.25 miles vertically

and this time correctly

horizontal component = 915 miles/h = 409meters/s * 2.3 s = 941meters horizontally

vertical component numbers ok but result in meters , not miles ,so

= 914.25 meters vertically

Answer 2

To find the total distance traveled, we need to calculate the horizontal and vertical components of the velocity. Using the given speed and angle, we can find the horizontal and vertical speeds. Then, we can calculate the total distance by multiplying the total time traveled by the horizontal speed.