If a skittle is one half inch by a quarter inch how many Skittles would it take to fill a pool that is 59x59 inches and 8 inches high?

Answer 1

We must first calculate the volume of one skittle. The volume of a cuboid is its length X width X height. The skittles length is .5in and its width is also .5in, finally its height according to the problem is .25in. Thus if we follow the formula:

.5in X .5in X .25in = .125in^3

Now we must find the area of the pool. Again we use the same formula:

59in X 59in X 8in = 27,848in^3

Now that we have both areas we can divide and find out the answer:

27,848in^3 / .125in^3 = 222,784 skittles.

The answer is 222,784 skittles.

Answer 2

To find the total volume of the pool in cubic inches, multiply the dimensions together (59 x 59 x 8 = 28,096 cubic inches). Then divide this total volume by the volume of one skittle (1/2 x 1/4 x 1/4 = 1/32 cubic inches) to determine how many skittles would fit in the pool, which is approximately 897,472 skittles.