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If air bubble were trapped in your solid beneath the liquid level in your density determination what error would result in the volume measurement?
Wiki User
∙ 16y ago
An air bubble in the solution would effectively increase the volume that you measure for the solid because you would coutn the volume of the bubble as the volume of the solid (but of course, it's just air!).
So if you measure the density of a solid by putting a weighed amount of the solid in a liquid (in which the solid is insoluble), then an air bubble in the solution would make the measured volume of the solid larger than it really is.
Density is found by taking the mass divided by volume. Assuming you find the mass correctly, if the measured volume is larger than the real volume, the denominator in the fraction (mass/volume) will be too big. If a denominator is too big, than the fraction is smaller.
Therefore an air bubble will cause you tounder estimate the density.
Wiki User
∙ 16y ago
If an air bubble were trapped in the solid beneath the liquid level during a density determination, it would displace some liquid volume, leading to a falsely lower volume measurement. This would result in a calculated density that is lower than the actual value.
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