density = mass / volume = 62g / 21.9 cm³ ≈ 2.8 g/cm³
This suggests the substance is lithium oxide (Li2O). The molar mass of Li2O is 29.88 g/mol. Therefore, 62g of Li2O is equivalent to 2.07 moles (62g / 29.88 g/mol = 2.07 mol).
To find the number of moles in 7.94g of sodium oxide, you need to divide the given mass by the molar mass of sodium oxide, which is 62g/mol. 7.94g / 62g/mol = 0.128 moles of sodium oxide.
To find the molarity of the solution, you first need to calculate the mass of ethylene glycol in the solution. Then convert it to moles using the molar mass of ethylene glycol. Finally, calculate the molarity by dividing the moles of ethylene glycol by the volume of the solution in liters.
usual 62g
To find the amount of oxygen used, we need to consider the difference in mass between sodium and sodium oxide. The mass increase is 16g (62g - 46g) which corresponds to the amount of oxygen used from the air. Therefore, 16g of oxygen from the air were used.
To find the mass of sodium oxide formed, we first need to calculate the moles of sodium used, which is 0.3 moles (6.9g / 23g/mol). Since one mole of sodium reacts with one mole of oxygen to form sodium oxide, the moles of sodium oxide formed is also 0.3 moles. The molar mass of sodium oxide (Na2O) is 62g/mol. Therefore, the mass of sodium oxide formed is 18.6 grams (0.3 moles * 62g/mol).
If you are referring to grams, 62g is approximately equal to 2.186985638 ounces.
A 20oz bottle of Squirt contains 62g of sugar.
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To find the number of moles in 1 kg of C2H6O2, we first need to calculate the molar mass of C2H6O2: (212.01) + (61.01) + (2*16.00) = 62.07 g/mol. Then, we convert 1 kg to grams: 1 kg = 1000 g. Finally, we divide the mass by the molar mass to find the number of moles: 1000 g / 62.07 g/mol = 16.12 moles.
At 313K, the solubility of potassium nitrate in water is approximately 62g/100g of water. To form a saturated solution in 50g of water, you would need roughly 31g of potassium nitrate.