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How do you prepare 10 mm solution with 4 m stock solution?
To prepare a 10 mm solution, you would dilute the 4 M stock solution. Use the formula C1V1 = C2V2, where C1 is the concentration of the stock solution (4 M), V1 is the volume of stock solution needed, C2 is the desired final concentration (10 mM), and V2 is the final volume of the solution. Calculate the volume of stock solution needed to achieve the desired concentration, then add solvent (usually water) to reach the final volume.
Explain how you would make 50 ml of 0.15 m NaOH solution from a 3.05 m NaOH solution?
To make 50 ml of 0.15 M NaOH solution, you would need to dilute the 3.05 M NaOH solution. Using the formula M1V1 = M2V2, where M1 is the initial concentration (3.05 M), V1 is the volume of stock solution needed, M2 is the final concentration (0.15 M), and V2 is the final volume (50 ml), you can calculate the volume of the stock solution needed to achieve the desired concentration. After calculating, you would mix the calculated volume of the 3.05 M solution with water to reach a final volume of 50 ml.
How would you prepare tetracycline stock solution?
To prepare a tetracycline stock solution, you would weigh out the appropriate amount of tetracycline powder and dissolve it in a suitable solvent, such as sterile water or ethanol. The concentration of the stock solution will depend on your experimental needs, but typically a concentration of 10-50 mg/ml is common. Remember to sterile filter the solution before storing it in aliquots at -20°C to prevent degradation.
What is the final percent concentration of the solution when 600 ml of 100 percent methanol added to 4400 ml of water?
The final percent concentration of the solution would be approximately 12.0% methanol. This is calculated by dividing the volume of methanol by the total volume of the solution (600 ml / 5000 ml) and then multiplying by 100 to get the percentage.
How do I make ml of 5 percent bleach solution from a 8.25 percent solution?
To make a 5% bleach solution from an 8.25% solution, you can use the dilution formula (C_1V_1 = C_2V_2), where (C_1) is the concentration of the stock solution (8.25%), (V_1) is the volume of the stock solution you need, (C_2) is the desired concentration (5%), and (V_2) is the final volume of the diluted solution. For example, to make 100 ml of a 5% solution, you would calculate (V_1 = \frac{C_2 \times V_2}{C_1} = \frac{5 \times 100}{8.25} \approx 60.61) ml of the 8.25% solution. Then, add enough water to reach a total volume of 100 ml.
How do you prepare 10 mm solution with 4 m stock solution?
To prepare a 10 mm solution, you would dilute the 4 M stock solution. Use the formula C1V1 = C2V2, where C1 is the concentration of the stock solution (4 M), V1 is the volume of stock solution needed, C2 is the desired final concentration (10 mM), and V2 is the final volume of the solution. Calculate the volume of stock solution needed to achieve the desired concentration, then add solvent (usually water) to reach the final volume.
Which statement best describes the process of making a solution by diluting a stock solution?
You can dilute by adding distilled water. When diluting, be sure to add the solution to water several times instead of adding water to the solution (especially if it is highly concentrated).
How many grams of ammonium sulfate are needed to make a .25 M solution at a concentration of 6M?
To make a 0.25 M solution of ammonium sulfate from a stock solution of 6 M, you would need to dilute the stock solution. The dilution equation is C1V1 = C2V2 where C1 and V1 are the concentration and volume of the stock solution, and C2 and V2 are the concentration and volume of the final solution. You would need to set up this equation to calculate the volume of the stock solution needed and then convert that volume to grams using the molar mass of ammonium sulfate.
How would you prepare 100 ml of 0.4 M magnesium sulfate from stock solution of 2 M magnesium sulfate?
To prepare 100 ml of 0.4 M magnesium sulfate from a 2 M stock solution, you would need to use the formula C1V1 = C2V2 where C1 is the initial concentration, V1 is the volume of stock solution to be used, C2 is the final concentration, and V2 is the final volume. Plugging in the values, you would calculate V1 to be 20 ml. Therefore, you would mix 20 ml of the 2 M stock solution with water to make a total volume of 100 ml to get a final concentration of 0.4 M magnesium sulfate.
How do you prepare a 6N NaOH solution from a 10N NAOH solution?
To prepare a 6N NaOH solution from a 10N NaOH solution, you would dilute the 10N solution by adding water. Use the dilution formula: C1V1 = C2V2, where C1 is the initial concentration (10N), V1 is the volume of stock solution needed, C2 is the final concentration (6N), and V2 is the final volume of the solution you want to make. Calculate the volume of the 10N solution needed and add water to reach the final desired volume for a 6N NaOH solution.
Explain how you would make 50 ml of 0.15 m NaOH solution from a 3.05 m NaOH solution?
To make 50 ml of 0.15 M NaOH solution, you would need to dilute the 3.05 M NaOH solution. Using the formula M1V1 = M2V2, where M1 is the initial concentration (3.05 M), V1 is the volume of stock solution needed, M2 is the final concentration (0.15 M), and V2 is the final volume (50 ml), you can calculate the volume of the stock solution needed to achieve the desired concentration. After calculating, you would mix the calculated volume of the 3.05 M solution with water to reach a final volume of 50 ml.
How many mL of a 2.0 m NaBr solution are needed to make 200 mL of 0.50 m NaBr?
You would need 50 mL of the 2.0 M NaBr solution to make 200 mL of 0.50 M NaBr solution. This can be calculated using the formula: (C1V1) = (C2V2), where C1 = concentration of stock solution, V1 = volume of stock solution, C2 = final concentration, and V2 = final volume.
How do you make 600 mL of a 1 molar solution of HCl using a 6 molar stock solution?
To prepare 600 mL of 1 M HCl solution from a 6 M stock solution, you can use the formula: M1V1 = M2V2, where M1 = concentration of stock solution, V1 = volume of stock solution needed, M2 = final concentration, and V2 = final volume. Plugging in the values: 6 M x V1 = 1 M x 600 mL. Therefore, V1 = 100 mL. Therefore, you would need to measure 100 mL of the 6 M stock solution and dilute it to 600 mL with water to make a 1 M HCl solution.
How would you prepare tetracycline stock solution?
To prepare a tetracycline stock solution, you would weigh out the appropriate amount of tetracycline powder and dissolve it in a suitable solvent, such as sterile water or ethanol. The concentration of the stock solution will depend on your experimental needs, but typically a concentration of 10-50 mg/ml is common. Remember to sterile filter the solution before storing it in aliquots at -20°C to prevent degradation.
What would be the concentration of a solution made by adding 250 mL of water to 45.0 mL of 4.2 M KOH?
To find the concentration of the final solution, you need to calculate the total moles of KOH before and after dilution. The initial moles of KOH can be found using the initial volume and concentration. Then, calculate the final volume of the solution after dilution and use it to determine the final concentration of KOH.
How many ml of 5 M are required to prepare 1000 ml of 0.02 M NaCl solution what is the dilution factor of this solution?
To prepare 1000 ml of 0.02 M NaCl solution, you would need 40 ml of 5 M NaCl solution, which you can calculate using the formula C1V1 = C2V2, where C1 is the concentration of the stock solution, V1 is the volume of the stock solution needed, C2 is the desired concentration, and V2 is the final volume. The dilution factor in this case would be 25, as you are diluting the 5 M solution 25 times to achieve the desired 0.02 M concentration.
You prepare a less concentrated H C l solution from a stock solution with 12m concentration. If you too 100g of the stock solution to prepare 4 MHCl solution how much water is needed to prepare o find solution 9density HCL(12) = 1,89/ml?
Image result for You prepare a less concentrated H C l solution from a stock solution with 12m concentration. If you too 100g of the stock solution to prepare 4 MHCl solution how much water is needed to prepare o find solution 9density HCL(12) = 1,89/ml? The concentration would be 0.76 mol/L.
