It depends, is the solution 15% salt or 15% saturatedwith salt? If it is 15% salt, is is 85% water. If it is 15% saturated, it is 5.385%.
Osmosis of water from a low concentration of salt to a high concentration
It would flow toward the weaker solution. The intent of osmosis is to gain equilibrium, so the 15 percent solution would gain sugar content until, if you allowed the osmosis to go to completion, the two solutions had the same amount of sugar in them. "Going to completion" doesn't necessarily mean 20 percent concentration on both sides. If you were to make a gallon bag out of dialysis membrane, fill it with 15 percent solution and put a stirrer in it, then drop it into a 25,000-gallon reaction vessel full of 25 percent solution with a stirrer in it, you might wind up with 24.9999999999 percent sugar solution in both bags.
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To make 15% alcohol from 40% alcohol you simply take 15cc of your 40% alcohol and put it into a graduated cylinder and fill the cylinder up the rest of the way with deionised water or distilled water to the 40cc mark on the graduated cylinder. you will then have 15% alcohol from 40%
To reduce a 25% acid solution to 10%, the water needed can be calculated using the formula: (10 x (25-10))/(10) = 1.5 liters. So, 1.5 liters of pure water must be mixed with the 10 liters of 25% acid solution to reduce it to 10%.
Dissolve 15 g salt in 100 mL water.
Osmosis of water from a low concentration of salt to a high concentration
Osmosis of water from a low concentration of salt to a high concentration
Osmosis of water from a low concentration of salt to a high concentration
It would flow toward the weaker solution. The intent of osmosis is to gain equilibrium, so the 15 percent solution would gain sugar content until, if you allowed the osmosis to go to completion, the two solutions had the same amount of sugar in them. "Going to completion" doesn't necessarily mean 20 percent concentration on both sides. If you were to make a gallon bag out of dialysis membrane, fill it with 15 percent solution and put a stirrer in it, then drop it into a 25,000-gallon reaction vessel full of 25 percent solution with a stirrer in it, you might wind up with 24.9999999999 percent sugar solution in both bags.
To dilute 500 gallons of a 31% solution to a 15% solution you would add 533.33 gallons of the dilutant. For example, if you have 500 gallons of a 31% saline solution you would add 533.33 gallons of water to create 1033.33 gallons of a 15% saline solution.
I think you may have misspelled your question. This always makes it a bit more difficult to answer. But I'm going to make the assumption that your solution was labelled "15% w/w" Is that about right? Well, then, what that means is that your solution contains 15 parts by weight of of the solute, and 85 parts by weight of the solvent. For example, a solution of 15 grams of salt and 85 grams of water is a 15% w/w solution of salt in water. By the way, w/w means "weight in weight".
The concentration of the diluted solution will be 15(300/1000) = 4.5 %, if the percent is expressed on a weight/volume basis.
Adding salt to water increases its density and lowers its freezing point. ---------------------- I've just completed a repeated experiment on the effects of salt and the freezing point of water. A saturated salt solution will not freeze at -15 degrees Celsius (my freezer temperature). At exactly -21.1 degrees Celsius the salt begins to crystallize out of the solution, along with the ice, until the solution completely freezes.
Mixing 80 liters of 15% solution and 520 liters of 90% solution will give 600 liters of 80% solution.
The percent of a solution is calculated by dividing the mass of the solute by the mass of the solution and multiplying by 100. In this case, the percent of the water solution containing 60 g of calcium chloride in a 400 g solution would be (60 g / 400 g) * 100 = 15%.
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