No. Its value varies with the value of n.
Homeostasis
An arithmetic sequence is a numerical pattern where each term increases or decreases by a constant value. This constant value is called the common difference.
If I understand the question correctly, the answer is 5N
The term "tenacity" is used to describe the constant, ongoing determination of someone. "Tenacity" is a noun that is related to the adjective "tenacious".
The term that refers to the opposite of a variable is its additive inverse. This means that for a variable x, its additive inverse is -x.
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The expression ( 7 - 8n - 100 ) can be simplified by combining the constant terms. It becomes ( -8n - 93 ). Thus, the simplified form of the expression is ( -8n - 93 ).
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28 - 8n
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The nth term of the sequence defined by the expression (8n - 7) is simply the output of that expression for a given integer (n). For any positive integer (n), you can find the nth term by substituting (n) into the formula, resulting in (8n - 7). For example, if (n = 1), the first term is (1), and if (n = 2), the second term is (9). Thus, the nth term represents a linear sequence where each term increases by 8 as (n) increases by 1.
The nth term of the sequence is expressed by the formula 8n - 4.
nth term = 5 +8n
8n-5 = 3
n=10/7. i did this one mentally. but are you sure its 8n minus negative 4n or is it 8n minus 4n? 8n- -4n does not equal 8n-4n 8n- -4n is the same as 8n+4n
It is: -3+8n-5 = 8n-8 when simplified