No. Its value varies with the value of n.
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∙ 11y agoNo, 8n is not a constant term. It is a term with a variable (n) attached to it, which means its value can change depending on the value of the variable. Constant terms are those that do not have variables attached to them.
Homeostasis
An arithmetic sequence is a numerical pattern where each term increases or decreases by a constant value. This constant value is called the common difference.
If I understand the question correctly, the answer is 5N
The term "tenacity" is used to describe the constant, ongoing determination of someone. "Tenacity" is a noun that is related to the adjective "tenacious".
The term that refers to the opposite of a variable is its additive inverse. This means that for a variable x, its additive inverse is -x.
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11
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3 11
28 - 8n
The nth term of the sequence is expressed by the formula 8n - 4.
nth term = 5 +8n
8n-5 = 3
First, look at the given problem. eg. (8n-3)^3. Mark the first term (8n) A then mark the second term (-3) B. Do this formula. (a+b)^3 = a^3 + 3a^2b + 3ab^2 + b^3
n=10/7. i did this one mentally. but are you sure its 8n minus negative 4n or is it 8n minus 4n? 8n- -4n does not equal 8n-4n 8n- -4n is the same as 8n+4n
It is: -3+8n-5 = 8n-8 when simplified
3 + 8n = -58n = -8n = -1