yes of course..
The distance traveled by the body would be twice the height h, as it goes up and then comes back down the same distance. However, the displacement would be zero, as the body ends up at the same position it started from, despite having traveled a distance.
Acceleration and displacement can be obtained from the velocity-time graph. Acceleration is the rate of change of velocity, which can be found as the slope of the velocity-time graph. Displacement can be determined by finding the area under the velocity-time graph, as it represents the distance traveled by an object.
Yes, it is possible. This can happen when an object changes direction but ends up at its starting point. For example, if a person walks a certain distance in one direction and then walks back the same distance, their average speed over the entire trip could be constant, but their average velocity would be zero since displacement is zero (ending at the same point).
Not without bad consequences. These require an element in the free state. Any of those in the human body will be very bad.
The energy expenditure for walking depends on factors like speed, weight, and distance traveled. On average, a person uses about 0.2 to 0.3 calories per kilogram of body weight per minute when walking at a moderate pace. This can be converted to approximately 0.84 to 1.26 Joules per kilogram of body weight per minute.
Displacement is equal to the distance traveled when the motion is along a straight line. This happens when the motion is in one direction without any changes in direction. In such cases, the magnitude of displacement is equal to the total distance traveled.
There's no way to answer that, because it can be a different number in every situation. It can never be greater than ' 1 ', but the actual number depends on how squiggly the route is between the starting point and the ending point.
The distance traveled by the body would be twice the height h, as it goes up and then comes back down the same distance. However, the displacement would be zero, as the body ends up at the same position it started from, despite having traveled a distance.
Yes, the distance covered by a body can be greater than the magnitude of displacement if the body moves along a curved path rather than a straight line. Distance is a scalar quantity that measures the total length of the path traveled, while displacement is a vector quantity that measures the shortest distance between the initial and final positions.
Displacement is a value predicated on the shortest distance between an initial and final position. If a "body" moves a certain distance and returns to its original origin it has not technically traveled any distance based on this definition. The displacement will therefore be zero
"Distance" covered is always greater than the magnitude of the displacement,unless the motion is in a straight line. In that case, distance and displacementare equal. Distance is never less than displacement.
"Distance" covered is always greater than the magnitude of the displacement,unless the motion is in a straight line. In that case, distance and displacementare equal. Distance is never less than displacement.
Distance:Length of the road you traveled to get from Here to There, includingall the turns and curves.Displacement:Straight-line length between Here and There, regardless of how youget there.Displacement is also a vector quantity, meaning it not only has a length number,but it also needs to include the straight-line directionfrom Here to There.
no way its defined in dat way we cant alter wat our ancestors follow.....
double of the radius means equal to diameter
The distance travelled by the body along the circular path is equal to the circumference of the circle, given by 2πR. The displacement of the body would be zero if it returns to its starting point, as displacement is the shortest distance between two points.
yes,displacement is the shortest distance covered by a body,so distance covered by a body may be greater than the displacement.