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The expression for acceleration due to gravity is
ge=GMe/r2Acceleration due to gravity is inversely proportional to the square of the distance between the center of the Earth and the object. The acceleration due to gravity produced in an object on the surface of the Earth is dependent on the radius of the Earth. Earth is not a perfect sphere (slightly bulging out at the equator) its radius decreases as we move from the equator to the poles. At the equator and at sea level its value is about 9.78 m/s2 and at the poles it is 9.83 m/s2. Its mean value is taken as 9.8 m/s2 for all calculations.
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What is the value of g when Equator moves towards pole?
The value of acceleration due to gravity (g) decreases as you move from the Equator towards the poles due to the centrifugal force caused by the Earth's rotation. At the Equator, this force counteracts some of the gravitational force, resulting in a lower g value compared to the poles.
Is the maximum value g at equator?
Yes, the maximum value of acceleration due to gravity (g) is at the equator because the centrifugal force due to the Earth's rotation reduces the effective gravitational force. This results in a maximum g value at the equator compared to other latitudes.
Why the motion of simple pendulum is slow at equator?
A pendulum will swing slowest when closest to the equator. Why is this? The time period, T, of the swing of a pendulum is given by: T=2π√(l/g) where l is the length of the pendulum and g is acceleration due to gravity. Because the Earth is spinning, there is a bulge at the equator and the poles are slightly flattened. Hence on the equator the radius to the centre of the earth is greater than the radius at the poles. The equatorial radius is 6378.1km while the polar radius is 6356.8 km The value of g at the Earth's surface relates to the values of the Earth's radius, r, at that point using an inverse square law ie g is proportional to 1/r2 At the North Pole, g is about 9.83m/s2, while at the equator, g is smaller, at only 9.79m/s2 . So the period of a pendulum will be longer (i.e. slowest) at the equator than at the pole
Why does the weight of a substance changes when weighed in a diff parts of world?
it is because earth is not perfectly spherical and also it spins on its Axis. The centrifugal force is greater at the equator and zero on poles. So the apparent weight at equators is lee because of centrifugal force. Also Earth is flattened at the poles which means that there is more acceleration due to gravity at poles[since g=GM/(R^2] In all, ate value of g ranges from around 9.7-9.9 on earth. This causes all the difference.
Why does the weight of an object change when it is moved from the equator to poles?
The weight of an object changes when it is moved from the equator to the poles due to the variation in the centrifugal force caused by the Earth's rotation. At the equator, the centrifugal force is strongest, causing a decrease in the apparent weight of an object. Conversely, at the poles, the centrifugal force is weakest, resulting in an increase in the apparent weight of an object.
Is there any difference between the value of g at the equator and the poles?
Yes, there is a difference in the value of acceleration due to gravity (g) at the equator and the poles. This is because the Earth is not a perfect sphere and has an oblate shape. At the equator, the centrifugal force due to the Earth's rotation reduces the effective gravity and makes g slightly smaller compared to the poles where this effect is minimal.
What is the value of g when Equator moves towards pole?
The value of acceleration due to gravity (g) decreases as you move from the Equator towards the poles due to the centrifugal force caused by the Earth's rotation. At the Equator, this force counteracts some of the gravitational force, resulting in a lower g value compared to the poles.
Is the maximum value g at equator?
Yes, the maximum value of acceleration due to gravity (g) is at the equator because the centrifugal force due to the Earth's rotation reduces the effective gravitational force. This results in a maximum g value at the equator compared to other latitudes.
Is there gravity at the equator?
we know g equalls GM/R*R. Therefore g is inversly proportional to R spuare. Where R is radius of the planet. The R at the equator is the greatest. Hence the value of g is min at the equator. The value if g increases from the equator to the poles.
Where is maximum value of g?
at the poles
How does the acceleration of gravity depend on it's distance from the center of the Earth?
acceleration due to gravity is given by, g=GM/R2 Hence distance from the earth increases g decreases and viceversa. So g at poles is greater than g at equator.
Why the motion of simple pendulum is slow at equator?
A pendulum will swing slowest when closest to the equator. Why is this? The time period, T, of the swing of a pendulum is given by: T=2π√(l/g) where l is the length of the pendulum and g is acceleration due to gravity. Because the Earth is spinning, there is a bulge at the equator and the poles are slightly flattened. Hence on the equator the radius to the centre of the earth is greater than the radius at the poles. The equatorial radius is 6378.1km while the polar radius is 6356.8 km The value of g at the Earth's surface relates to the values of the Earth's radius, r, at that point using an inverse square law ie g is proportional to 1/r2 At the North Pole, g is about 9.83m/s2, while at the equator, g is smaller, at only 9.79m/s2 . So the period of a pendulum will be longer (i.e. slowest) at the equator than at the pole
What is the value of g at the poles of the earth?
g the acceleration due to gravity is 9.832 metres per second2 at the poles.
What is the value of g being used as a constant and why is this value used?
The constant g typically used in physics represents the acceleration due to gravity, which is approximately equal to 9.81 m/s^2 on the surface of the Earth. This value is used because it allows us to predict the effect of gravity on objects in free fall or in motion.
Why does the weight of a substance changes when weighed in a diff parts of world?
it is because earth is not perfectly spherical and also it spins on its Axis. The centrifugal force is greater at the equator and zero on poles. So the apparent weight at equators is lee because of centrifugal force. Also Earth is flattened at the poles which means that there is more acceleration due to gravity at poles[since g=GM/(R^2] In all, ate value of g ranges from around 9.7-9.9 on earth. This causes all the difference.
Is the value 'g' same everywhere on the surface of the earth?
No, the value of acceleration due to gravity ('g') varies slightly depending on the location on Earth. Factors such as altitude, latitude, and geology can influence the value of 'g'. The average value of 'g' is approximately 9.81 m/s^2.
Why does the weight of an object change when it is moved from the equator to poles?
The weight of an object changes when it is moved from the equator to the poles due to the variation in the centrifugal force caused by the Earth's rotation. At the equator, the centrifugal force is strongest, causing a decrease in the apparent weight of an object. Conversely, at the poles, the centrifugal force is weakest, resulting in an increase in the apparent weight of an object.
