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Earn +20 ptsQ: Math conversions. How do I convert 2.87 Liters to mL?
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How many liters does a tank 60 inches long by 48 inches high by 23 inches wide hold of furnace oil?
To calculate the volume of the tank in cubic inches, multiply the length, width, and height: 60" x 48" x 23" = 66240 cubic inches. To convert cubic inches to liters, divide by 61.02 (since 1 cubic inch is approximately 0.0163871 liters): 66240 cubic inches / 61.02 ≈ 1084.7 liters. Therefore, the tank holds approximately 1084.7 liters of furnace oil.
What is 287 divided by 13?
22.0769
What is equivalent to the meter reading of 287 micro-amps?
A current of 287 microamps, which is 0.000287 amps.
How was OJ 287 discovered?
OJ 287 was discovered in 1968 as a radio source by the Ohio State University Radio Telescope. It was later recognized as an active variable source in radio and optical bands in the early 1970's.
What size motor is a 4.7 liter?
A 4.7 liter engine typically equates to a 287 cubic inch engine.
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