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(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied

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12y ago
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1mo ago

The momentum of the first car is determined by its mass and velocity. The higher the mass or velocity of the car, the greater its momentum. When the first car collides with the second car, it imparts an impulse based on its momentum, transferring some of its momentum to the second car in the form of a force over a short period of time, leading to a change in the second car's velocity.

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Q: One railroad car rolls toward another Describe the properties of the first car that determine its momentum and how it would impart an impulse to the second car?
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