To write 0.00145 in scientific notation, we first move the decimal so only one figure appears to the left of the decimal. Here's that shift: 0.00145 => 1.45 But we need to account for the movement with a power of ten. Moving the decimal to the right, which we just did, will mean a negative power of ten. And the power of ten will be an integer that is equal to the number of places we moved the decimal. In this case, we moved it 3 places. That means our exponent on the 10 will be a -3. Here it is: 1.45 x 10-3 And we're done.
That the last number is 5 means you round the second to last one up. This gives you .0943. However, 3 is the last number now, and that doesn't let one round up. So you are at .094. Four is the last number, and it does not allow you to round up.
So you are left with the last two digits of .09, which are the two significant figures.
45.0 is the 44.981 to 3 significant figures.
8 By definition, all the figures are significant (no rounding off appears to have taken place). There are eight significant figures.
To round 35670.06 to 4 significant figures, we count from the first non-zero digit from the left. The first four digits are 3, 5, 6, and 7. The digit after 7 is 0, which is less than 5, so we keep the 7 and round down. Therefore, 35670.06 rounded to 4 significant figures is 35670.
Yes, 510 rounded off to 3 significant figures would be 510.
If the zeros are significant figures then 900 is correct to 3 significant figures. If rounding off has occurred then the answer could be 1 sf or 2sf. For example : If the original number was 903 and rounding off to the nearest ten was required then 900 is correct to 2 significant figures. If the number was 927 and rounding off to the nearest hundred was required then 900 is correct to 1 significant figure.
88930371.007 to 2 significant figures is 89000000
0.036 The significant figures are indicated by the square brackets 0.0[35550], so we round this part of the figure.
It depends on how many significant digits you want to round it off to.
what is the round off of 124.36?
93
6.71 is 6.7050 is rounded to three significant figures.
To round 48100231 Joules to two significant figures, you would round it to 48000000 Joules since the first two significant figures are 4 and 8. The trailing zeros are not significant.
Rounding to different numbers of significant figures, the greatest result is 22,000.21 987 round off theto its greatest value what is answer.
If you are rounding off to two significant figures the result is 33.Sixes always round up to the next higher digit i.e.296 to two significant figures is 30 *101
Simply cut off the extra digits: 5.00
1.0 x 10^2
Simply cut off the extra number: 65.7