No, the equation you provided is not balanced. The correct balanced equation for the combustion of propane is C3H8 + 5 O2 β 3 CO2 + 4 H2O. The equation you provided appears to have a typographical error.
The balanced reaction of propane (C3H8) with oxygen (O2) to form carbon dioxide (CO2) and water (H2O) is: C3H8 + 5O2 β 3CO2 + 4H2O
The combustion equation of propane is:C3H8 + 5 O2 = 3 CO2 + 4 H2O
The balanced chemical equation for the combustion of propane (C3H8) with oxygen (O2) to form carbon dioxide (CO2) and water (H2O) is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O
5
C3h8 + 5o2 -> 3co2 + 4h2o
The reaction of C3H8 (propane) with 5O2 (oxygen) is a combustion reaction. It produces carbon dioxide (CO2) and water (H2O) as products.
The chemical equation C3H8 + 5O2 -> 3CO2 + 4H2O represents the combustion of propane (C3H8) with oxygen (O2) to produce carbon dioxide (CO2) and water (H2O).
C3H8 + 5O2 = 3CO2 + 4H2O, so the coefficient for O2 is 5
C3H8 + O2 ---------> CO2 + H2O UNBALANCED C3H8 + 5O2 ---------> 3CO2 + 4H2O BALANCED
No, the equation you provided is not balanced. The correct balanced equation for the combustion of propane is C3H8 + 5 O2 β 3 CO2 + 4 H2O. The equation you provided appears to have a typographical error.
The reaction is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O
The balanced reaction of propane (C3H8) with oxygen (O2) to form carbon dioxide (CO2) and water (H2O) is: C3H8 + 5O2 β 3CO2 + 4H2O
The chemical reaction is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O
The combustion equation of propane is:C3H8 + 5 O2 = 3 CO2 + 4 H2O
The balanced chemical equation for the combustion of propane is:C3H8 + 5O2 --> 3CO2 + 4H2O
The balanced chemical equation for the combustion of propane (C3H8) with oxygen (O2) to form carbon dioxide (CO2) and water (H2O) is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O