3/17x100
NH3 is its own compound.The elements in NH3 are nitrogen and hydrogen.
No, hydrocarbons contain carbon (C) and hydrogen (H) NH3 is a compound of nitrogen and hydrogen.
Put a 2 to NH3 first.Then a 3 to Hydrogen.
H stands for Hydrogen.N stands for Nitrogen.
In Haber’s process, the equivalent weight of ammonia (NH3) is calculated based on its molar mass and the number of moles of hydrogen ions (H⁺) it can donate or accept. The molar mass of NH3 is approximately 17 g/mol. Since one mole of NH3 can donate one mole of H⁺, its equivalent weight is also 17 g. Thus, the equivalent weight of NH3 in the context of Haber’s process is 17 g/equiv.
Grab yourself a periodic table and look up the atomic masses of nitrogen and hydrogen, which are the constituent elements of NH3 (which is ammonia.) Nitrogen is 14, and hydrogen is 1. Now look at the formula. It says you have 1 nitrogen and 3 hydrogens. Add it up: 14+1+1+1=17, for a total "molar mass" of 17 grams per mole. Now use the concept of percent (part divided by total) to get your percent composition by mass. 14/17=0.82, 82% nitrogen. 3/17=0.18, so 18% hydrogen. You can do that now for any compound!
170 kg = 170,000g NH3 = 170,000g / 17.0g/molNH3 = [10,000 molNH3] * 3moleH2 / 2moleNH3= 15,000 mole H2 needed to produce 170 kg NH3
The molar mass of ammonia (NH3) is 17.03 g/mol. Hydrogen's molar mass is 1.01 g/mol. The mass of hydrogen in ammonia is 3.03 g (3*1.01). To find the mass percentage of hydrogen in ammonia: (3.03 g / 17.03 g) * 100% ≈ 17.8%.
The molar mass of NH3 is 17.03 g/mol. The molar mass of nitrogen is 14.01 g/mol. To find the percent composition of nitrogen in NH3, divide the molar mass of nitrogen by the molar mass of NH3 and multiply by 100. So, (14.01 g/mol / 17.03 g/mol) x 100 = 82.22%.
In ammonia (NH3), there are three hydrogen atoms for every molecule. The molar mass of ammonia is 17 grams per mole. To find the mass of hydrogen in 150 grams of ammonia, you can calculate as follows: 150 g x (3 g H2 / 17 g NH3) = 26.47 g of hydrogen.
NH3 is its own compound.The elements in NH3 are nitrogen and hydrogen.
To find the number of moles of NH3 in 107.1g, divide the given mass by the molar mass of NH3. The molar mass of NH3 is 17.03 g/mol. ( \frac{107.1 , \text{g}}{17.03 , \text{g/mol}} ≈ 6.29 , \text{mol} ) of NH3 are present.
The formula shows that there are three times as many atoms of hydrogen as of nitrogen in the compound. The gram atomic masses are 1.00794 for hydrogen and 14.0067 for nitrogen. Therefore, the percent by mass of hydrogen in the compound is 100{[3(1.00794)]/[3(1.00794) + 14.0067] or 17.7553 %, to the justified number of significant digits.
Nitrogen has an average atomic mass of about 14 while hydrogen has an average atomic mass of about 1, so the total molecular mass of NH3 is about 17. From this we find that the mass percentage of N in NH3 is about 14/17 = 82%. To get more precise numbers, look up the exact atomic masses from a periodic table.
nitrogen weighs 14, hydrogen weighs 1, so NH3 weighs 14+(3x1)=17grams
To find the molar mass of NH3, you would add up the atomic masses of the atoms it contains. In this case, nitrogen (N) has a molar mass of around 14.01 g/mol and hydrogen (H) has a molar mass of around 1.01 g/mol. Therefore, the molar mass of NH3 would be approximately 14.01 + 3(1.01) = 17.03 g/mol.
To calculate the mass of H2 needed to produce 13.14g of NH3, you can use the molar ratio between H2 and NH3. From the balanced chemical equation for the reaction, you can see that 2 moles of NH3 are produced for every 3 moles of H2 consumed. First, calculate the number of moles of NH3 using its molar mass, then use the molar ratio to find the moles of H2 needed, and finally convert the moles of H2 into grams.