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13.3g

C + O2 = CO2

m(C)=4g => n(C)=4/12=0,333mol

m(O2)=10.67g => n(O2)=10.67/28=0,381mol

we have excess of oxigen

n(CO2)=n(C)=0,333

m(CO2)=0.333*40=13.3g

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