13.3g
C + O2 = CO2
m(C)=4g => n(C)=4/12=0,333mol
m(O2)=10.67g => n(O2)=10.67/28=0,381mol
we have excess of oxigen
n(CO2)=n(C)=0,333
m(CO2)=0.333*40=13.3g
The balanced equation is: 2C + O2 -> 2CO2. First, determine the moles of C and O2: 4g C / 12 g/mol = 0.33 mol C and 10.67g O2 / 32 g/mol = 0.33 mol O2. From the balanced equation, 2 moles of C produces 2 moles of CO2, so 0.33 mol C will produce 0.33 mol CO2. Since CO2 has a molar mass of 44 g/mol, the total grams of CO2 produced will be: 0.33 mol CO2 x 44 g/mol = 14.52 grams of CO2.
38
To find the mass of one seed, you would divide the total mass of the seeds (200 grams) by the total number of seeds (1000). Therefore, each seed would have a mass of 0.2 grams (200 grams / 1000 seeds = 0.2 grams per seed).
The atomic mass number of that isotope. So C14 has a molecular mass of 14 grams/mole U238, 238 grams/mole
In chemistry, the outcome of a reaction must have the same mass as the initial state. This means that if you have 32g of oxygen and 4g of hydrogen, you just have to add the numbers to discover the original mass (in this case, 36g).
The equation of the reaction is Fe + HCl → H₂ + FeCl₂. Since one mole of iron produces one mole of hydrogen gas, the molar ratio between Fe and H₂ is 1:1. Thus, the total number of grams of H₂ produced when 116 grams of iron is reacted would be 2 grams (1 mole of hydrogen gas weighs 2 grams).
Another number added to a number is the sum (total) of the two numbers.
A number being added to another number is called an addend. The total of the numbers added together is called the sum.
Another number added to a number is the sum (total) of the two numbers.
11 grams because all is reacted and there is no reactant left over, although if there were only 3 grams of carbon there would have to be 6 grams of oxygen for this to be viable as carbon dioxide is CO2 so the question asked was itself wrong.
The total number of protons.
369 must be added to get 518
The balanced equation is: 2C + O2 -> 2CO2. First, determine the moles of C and O2: 4g C / 12 g/mol = 0.33 mol C and 10.67g O2 / 32 g/mol = 0.33 mol O2. From the balanced equation, 2 moles of C produces 2 moles of CO2, so 0.33 mol C will produce 0.33 mol CO2. Since CO2 has a molar mass of 44 g/mol, the total grams of CO2 produced will be: 0.33 mol CO2 x 44 g/mol = 14.52 grams of CO2.
When 1.0 mole of O2 is completely consumed in the reaction to form NO, 1.0 mole of NO is produced since the balanced equation for the reaction is 2 O2 + 2 N2 -> 2 NO. This means that the mole ratio between O2 and NO is 1:1.
Grams of fat isn't that important, Better look at your BMI, your lifestyle, and total number of calories instead.
The sum is the total when numbers are added together, the product is the total when they are multiplied.
This serial number was produced between 1936 and 1954 out of a total of 199,891 Model 121s produced.