Assuming Cl2 is in its gaseous form at standard temperature and pressure (STP), the volume would be 11.2 liters. This is calculated using the ideal gas law equation: V = (m/M) * (RT/P), where m is the mass of the gas, M is the molar mass of the gas, R is the ideal gas constant, T is the temperature, and P is the pressure.
For 2HCl(g) ==> H2(g) + Cl2(g) the Keq = [H2][Cl2]/[HCl]^2
You can use the ideal gas law to solve this problem. First, convert 0.30 g of Cl2 to moles. Then use the molar volume of gas at STP (22.4 L/mol) to determine the volume of Cl2 gas needed. Convert this volume to milliliters (1 L = 1000 mL) to find the answer.
The volume of the object can be calculated using the formula: volume = mass / density. Plugging in the values (mass = 25 g, density = 0.45 g/ml), the volume would be 55.56 ml.
The density of the object is 20 g/cm^3. Density is calculated by dividing the mass of the object by its volume. In this case, 500g รท 25cm^3 = 20 g/cm^3.
The density of Cl2 gas at standard temperature and pressure (STP) is approximately 3.214 g/L.
For 2HCl(g) ==> H2(g) + Cl2(g) the Keq = [H2][Cl2]/[HCl]^2
You can use the ideal gas law to solve this problem. First, convert 0.30 g of Cl2 to moles. Then use the molar volume of gas at STP (22.4 L/mol) to determine the volume of Cl2 gas needed. Convert this volume to milliliters (1 L = 1000 mL) to find the answer.
For 2HCl(g) ==> H2(g) + Cl2(g) the Keq = [H2][Cl2]/[HCl]^2
H2 (g) + Cl2 (g) --> 2 HCl (g) 25.00 g HCl x 1 mol HCl x 1 mol Cl2 x 70.90 g Cl2 = 24.3 g Cl2 are needed. ................... 36.46 g HCl . 2 mol HCl .. 1 mol Cl2
The volume of the object can be calculated using the formula: volume = mass / density. Plugging in the values (mass = 25 g, density = 0.45 g/ml), the volume would be 55.56 ml.
The formula for density is density = mass/volume. In this case, the mass is 25 g and the volume is 25 ml. Therefore, the density of water in this scenario would be 1 g/ml.
Cl2(g) + F2(g) -> 2ClF(g)
To find the volume, you can use the formula: Volume = Mass / Density. Plugging in the values gives Volume = 282.5 g / 11.3 g/cm^3 = 25 cm^3. So, the volume of the lead is 25 cm^3.
The equilibrium constant (K eq) for the reaction 2HCl(g) โ H2(g) + Cl2(g) would be [H2][Cl2]/[HCl]^2, where the square brackets indicate the molar concentrations of the respective species at equilibrium.
The density of the object is 20 g/cm^3. Density is calculated by dividing the mass of the object by its volume. In this case, 500g รท 25cm^3 = 20 g/cm^3.
The decomposition reaction for PCl5 is: 2 PCl5 (g) โ PCl3 (g) + Cl2 (g)
The density of the substance is 0.25 g/cm^3. This is calculated by dividing the mass (25 g) by the volume (100 cm^3).