Possible values of quantum numbers in order of n,l,m,s in the second shell:
The possible values for the magnetic quantum number (m1) for 8s electrons range from -0 to 0, which means there is only one possible orientation in space. The m1 quantum number specifies the orientation of the electron's magnetic moment in an external magnetic field.
The spin quantum number can have two possible values: +1/2 or -1/2.
Quantum numbers are values used to describe various characteristics of an electron in an atom, such as its energy, angular momentum, orientation in space, and spin. These numbers are used to define the allowed energy levels and possible configurations of electrons in an atom.
The four quantum numbers for scandium are n, l, m_l, and m_s. The principal quantum number (n) determines the energy level of the electron, with scandium typically having n=3. The azimuthal quantum number (l) specifies the shape of the orbital, with possible values of 0 to n-1. The magnetic quantum number (m_l) indicates the orientation of the orbital in space, ranging from -l to +l. The spin quantum number (m_s) describes the spin of the electron, which can be either +1/2 or -1/2.
In theory, the number of electrons with each quantum number is not limited. However, for any given "main quantum number" (n), the number of electrons having the other quantum numbers is limited - but it depends on the value of "n". For more information, the Wikipedia article on "quantum number" seems to give a good overview.
The quantum numbers for Br (Bromine) are: Principal quantum number (n): Can have values 1 to infinity Azimuthal quantum number (l): Can have values 0 to (n-1) Magnetic quantum number (m): Can have values -l to +l Spin quantum number (s): Can have values +1/2 or -1/2
The possible values for the magnetic quantum number (m1) for 8s electrons range from -0 to 0, which means there is only one possible orientation in space. The m1 quantum number specifies the orientation of the electron's magnetic moment in an external magnetic field.
the spin quantum number has only two possible values__(+ 1/2 & -1/2)
To determine the total degeneracy for a particle in a 3-dimensional cube with quantum numbers, you would need to calculate the number of possible states the particle can occupy based on the quantum numbers. This involves considering the possible values of the quantum numbers and how they combine to give different energy levels and states for the particle within the cube. The total degeneracy is the sum of all these possible states.
The spin quantum number can have two possible values: +1/2 or -1/2.
For a principle quantum number 3, there are three possible sub-shells. These are 3s, 3p, 3d. Azimuthal quantum no. is less than principle quantum number. There for 3s it is 0, for 3p it is 1, for 3d it is 2.
The number of orbitals in a given subshell, such as the 5d subshell, is determined by the number of possible values of the magnetic quantum number. Each orbital in a subshell is designated by a unique set of quantum numbers, including the magnetic quantum number that specifies the orientation of the orbital in space. In the case of the d subshell, there are five possible values for the magnetic quantum number (-2, -1, 0, 1, 2), so there are five orbitals in the 5d subshell.
Quantum numbers can be defined as a number that occurs in the hypothetical expression for the value of some quantized property of a subatomic particle, atom, or molecule and can only have certain integral or half-integral values.
"l" is known as the angular momentum quantum number. Principal Quantum Number = n Angular Momentum " " = l Magnetic " " = ml Spin " " = ms (Only possible values are 1/2 and -1/2) Search "Permissible Values of Quantum Numbers for Atomic Orbitals" for the values. You basically have to understand the concepts & be able to recreate the chart for tests, otherwise you can blindly memorize it. The chart should be in your book.
There can be two electrons with those quantum numbers in an atom. Each electron is completely described by four quantum numbers. The one that's missing in the list provided is ms, which can have only two possible values (+1/2 and -1/2).
The set of four quantum numbers for the final electron in Cobalt (Co) can be determined as follows: Principal quantum number (n): The energy level of the electron in the atom, which for Cobalt is typically 3. Azimuthal quantum number (l): Describes the shape of the orbital, which can be 0 to (n-1). For Cobalt, the possible values could be 0, 1, or 2. Magnetic quantum number (m_l): Specifies the orientation of the orbital in space, ranging from -l to +l. For Cobalt, this could be -1, 0, or +1 based on the possible values of l. Spin quantum number (m_s): Indicates the spin of the electron, which is either +1/2 (up) or -1/2 (down). For the final electron in Cobalt, the specific values for these quantum numbers would depend on the electron configuration and the particular orbital the electron occupies.
ms = -1/2