For a 10 amp, 250 volt circuit, you should install a circuit breaker rated for at least 10 amps and 250 volts. A common option would be a single-pole, 10 amp circuit breaker designed for 240-250 volt applications. Be sure to check the specifications and compatibility with your specific electrical panel.
Assuming each 250-watt fixture draws about 2.1 amps, you could install up to 9 fixtures on a twenty-amp breaker. This calculation is based on the formula for determining amperage (Watts / Volts = Amps) and the maximum continuous load of an electrical circuit being 80% of the circuit's rated capacity.
The horsepower rating of a 250 amp circuit breaker can be determined by using the formula: HP = (V x A x Eff) / 746, where V is the voltage (in volts), A is the amperage (in amps), and Eff is the efficiency factor (usually 0.8 for typical motors). Plug in the values and calculate to find the horsepower rating of the circuit breaker.
No, the electrical insulation rating of a 15 amp duplex receptacle is only rated at 130 volts. The 15 amp 240 volt receptacle is rated at 250 volts. The 240 volt receptacle also has a tandem pin configuration instead of the parallel configuration of the 120 volt device. The different pin configuration is so that a 120 volt electrical device can not be plugged into a 240 voltage receptacle.
The circuit breaker is used to protect the conductor that is connected to it from an overload condition. On a motor load the breaker has to be sized 250% of the motors full load amperage. Some circuits can be only loaded to 80% capacity and this is governed by the sizing of the breaker. Without knowing what the load amperage is, this question can not be answered.
A 250 volt outlet with 30 amps can handle up to 7500 watts (250V x 30A = 7500W) of power. This calculation is based on the formula Watts = Volts x Amps.
My calculation shows 15 such fixtures on that circuit.
The circuit breaker is sized to the full load amps of the motor times 250%.
The breaker should be sized to 250% of the motor's full load amperage.
Assuming each 250-watt fixture draws about 2.1 amps, you could install up to 9 fixtures on a twenty-amp breaker. This calculation is based on the formula for determining amperage (Watts / Volts = Amps) and the maximum continuous load of an electrical circuit being 80% of the circuit's rated capacity.
Tripping is caused by excessive current, which is usually the result of a fault in cable or equipment. The circuit breaker is there for safety and it trips to prevent a possible fire starting.
The horsepower rating of a 250 amp circuit breaker can be determined by using the formula: HP = (V x A x Eff) / 746, where V is the voltage (in volts), A is the amperage (in amps), and Eff is the efficiency factor (usually 0.8 for typical motors). Plug in the values and calculate to find the horsepower rating of the circuit breaker.
No, the electrical insulation rating of a 15 amp duplex receptacle is only rated at 130 volts. The 15 amp 240 volt receptacle is rated at 250 volts. The 240 volt receptacle also has a tandem pin configuration instead of the parallel configuration of the 120 volt device. The different pin configuration is so that a 120 volt electrical device can not be plugged into a 240 voltage receptacle.
In this situation, to calibrate a transmitter you need a power circuit and communicator circuit. The Hart communicator used in the calibration process is connected to the power source circuit in parallel. The power source circuit is the one that has ammeter, 250 Ohm resistor, and power source all connected in series. As the transmitter sends output mA, it creates volt drop across the 250 Ohm resister. Let's say the volt drop across the resistor was 1 Volt. Now, back to the Hart communicator. It is a load, meaning there will be a volt drop across the Hart communicator. Since it is in parallel with the power circuit, it is also parallel with the resistor. So, the 1 volt drop across the 250 Ohm resistor will also make 1 volt drop across the Hart communicator. Technically speaking, the 1 volt drop across the Hart communicator is only true if its resistor is also 250 Ohm. However, it does NOT matter what voltage drop is in the Hart communcator. It only sees the "relative" voltage drop changes to measure the changes in transmitter outputs.
The circuit breaker is used to protect the conductor that is connected to it from an overload condition. On a motor load the breaker has to be sized 250% of the motors full load amperage. Some circuits can be only loaded to 80% capacity and this is governed by the sizing of the breaker. Without knowing what the load amperage is, this question can not be answered.
A 250 volt outlet with 30 amps can handle up to 7500 watts (250V x 30A = 7500W) of power. This calculation is based on the formula Watts = Volts x Amps.
A circuit breaker is dual function. The only time it will trip is if it senses a fault current that is rated higher than the breaker rating (short circuit). The other trip condition is if the circuit is overloaded and is drawing a current higher than the breaker rating. On breakers that protect motor feeders the breaker has to be rated 250% higher than the motors full load amperage. If the breaker has lots of use and is used for a switch being manually turned off and on will weaken the trip value of the breaker. If you have access to, or know an electrician, a clamp on amp meter on the conductor that the breaker feeds will tell you what is happening. Clamp the line and turn on the load to see exactly what the current is. If, like you say, the breaker is properly rated and the current is within the breaker limits then change out the breaker for a new one.
The formula you are looking for is W = I x E, Watts = Amps x Volts.