10000 = 415 * i
i = 10000/415 = 24 a
<<>>
The formula you are looking for when KVA is known is I = KVA x 1000/1.73 x E = 10000/1.73 x 415 = 10000/240 = 41.6 amps.
To calculate the current per phase, use the formula: Current (I) = Power (P) / (Square Root(3) x Voltage (V)). For an 18kW motor at 415V, the current per phase will be: 18,000W / (1.732 x 415V) ≈ 24.5A per phase.
Yes, for a 15HP 3-phase 415V AC motor, each phase will draw approximately 26 Amps of current when running under normal operating conditions. This results in a total current draw of 26 Amps per phase for the motor.
In three phase: I = (three phase VA) / (sqrt(3) x (phase to phase voltage)) for single phase: I = (single phase VA) / ((phase to neutral voltage)) keep in mine three phase VA = 3 x (single phase VA), and phase to phase voltage = 1.732 x (phase to neutral voltage) Therefore the single phase and three phase currents are the same (ie, the three phase currents are the same in all three phases, or balanced). But don't get available current and available power confused (KVA is not the same as KW).
to calculate the motor full load current one should know motor power factor, supply voltage and phase of supply. Assuming your motor is with 0.85 pf and 3 phase, 415V source then P = (Sqrt3)*V*I*pf 18500 = 1.732*415*0.85*I hence I = 30.2A
Yes, you can step down 415V to 110V using a transformer. The transformer will reduce the voltage to the desired level, allowing you to power devices that require 110V. Be sure to use a transformer rated for the appropriate voltage conversion.
To calculate the current per phase, use the formula: Current (I) = Power (P) / (Square Root(3) x Voltage (V)). For an 18kW motor at 415V, the current per phase will be: 18,000W / (1.732 x 415V) ≈ 24.5A per phase.
415V 3 phase is the line to line voltage. The line to neutral of this supply is 230V single phase. Therefore you use one of the phases and the neutral.
In India its 415V, 50Hz.
Yes, for a 15HP 3-phase 415V AC motor, each phase will draw approximately 26 Amps of current when running under normal operating conditions. This results in a total current draw of 26 Amps per phase for the motor.
Current shall increase while you apply 415V for operating it and will decrease the rpm to a much low level.
Yes, it will run drawing little more extra current in similar conditions. The motor is expected to be running in lesser rpm as well.
The single phase voltage in India is 230v when we check with the phase and the nutral single line
The line current would be the same if the motor were connected in delta. The current can be based on the rule of thumb which says 7 amps must be allowed for a 1-HP single-phase motor on 240 v. A 2.2 kW motor is three times as powerful, and on a three-phase supply of the same voltage (240/415) it would draw 7 amps.
apply 3 phase voltage(415V) to the winding whose magnetising current is to be found and open circuit another winding. now measure current using tong tester or connecting an ammeter in series between supply and winding.
In three phase: I = (three phase VA) / (sqrt(3) x (phase to phase voltage)) for single phase: I = (single phase VA) / ((phase to neutral voltage)) keep in mine three phase VA = 3 x (single phase VA), and phase to phase voltage = 1.732 x (phase to neutral voltage) Therefore the single phase and three phase currents are the same (ie, the three phase currents are the same in all three phases, or balanced). But don't get available current and available power confused (KVA is not the same as KW).
0.073 assuming 0.85 power factor
5 hp moto 1500 rpm 3 phase winding calculation